3 years ago

-2(3x-4)=4(5x-11) Solve for x

Mathematics

2 answers:

sveta [45]3 years ago

6 0

-2(3x-4)=4(5x-11)

-6x+8=20x-44

8+44=26x

26x=52

x=52/26

your answer will be x=2

Andreyy893 years ago

3 0

Answer:

x=2

Step-by-step explanation:

-2(3x-4)=4(5x-11)

-6x+8=20x-44

8+44=26x

26x=52

x=52/26

x=2

You might be interested in

The coordinates of the following points represent the vertices of a

Setler [38]

I dont know i wish i could help ask me anytime with any thing else

7 0

3 years ago

Read 2 more answers

John pushes forward on a car with a force of 125 N while Bob pushes

EleoNora [17]

THE CORRET IS THE LETTER C

8 0

3 years ago

Read 2 more answers

I Need Help please;-;.

cluponka [151]

:( sorry idk to this question

4 0

3 years ago

Read 2 more answers

The diameter of a varicocele measures more than _____ millimeters (mm). * 5 points 5 3 4 2

Rudiy27

Answer:

A varicocele measures more than 2 mm in diameter.

Step-by-step explanation:

pampiniform plexus veins measuring more than. 2 mm in diameter at rest and which increased in diameter by 1 mm, and subjective color Doppler.

7 0

2 years ago

Two vertical posts stand side by side. One post is 8 feet tall and the other is 17 feet tall. If a 24 foot wire is stretched bet

lianna [129]

Answer:

The distance between the posts is $3\sqrt{55}$ feet.

Step-by-step explanation:

In the attached figure, let DB and AC be the posts and let AD be the wire attached to the top of the posts.

BC is the distance between the posts and we need to find BC.

Note that BC = DE

Also, EC = DB = 8m and AE = AC - EC = 17 - 8 = 9 m.

Now, in the right triangle ADE,

$AD^{2} =AE^{2} +DE^{2}$

$24^{2} =9^{2} +DE^{2}$

$DE^{2} =24^{2} -9^{2}$

= (24+9) (24-9)

= 33(15)

= (3 × 11) × (3 × 5)

$DE=3\sqrt{55}$

Since DE = BC,

$BC=3\sqrt{55}$

Hence, the distance between the posts is $3\sqrt{55}$ feet.

7 0

3 years ago