<span>1. </span><span>Nia has 2, 3, 8, 9 and 5 in her
cards. How can she arrange it to be an even numbers with the 2 in the ten
thousands place.
Now, Nia has 5 cards, that means, the biggest value she can have is ten
thousands which is stated to be 2.
=> 20 000
=> We still have 3, 8, 9 and 5
=> Let’s have 3 thousands, which is
also an even number
=> let’s have 5 as hundreds, also an even number
=> We can have 9 tens, which is also an even number
=> and last is 8 ones, which is also an even number
Thus, the number will be:
=> 23 598, this is an even number because it can be divide by 2
=> 11 799
</span>
2x² + 12x + 11 - (x - 4)²
2x² + 12x + 11 - 1(x - 4)²
2x² + 12x + 11 - 1(x - 4)(x - 4)
2x² + 12x + 11 - 1(x(x - 4) - 4(x - 4))
2x² + 12x + 11 - 1(x(x) - x(4) - 4(x) + 4(4))
2x² + 12x + 11 - 1(x² - 4x - 4x + 16)
2x² + 12x + 11 - 1(x² - 8x + 16)
2x² + 12x + 11 + 1(x²) + 1(8x) - 1(16)
2x² + 12x + 11 + x² + 8x - 16
2x² + x² + 12x + 8x + 11 - 16
3x² + 20x - 5
Might be A, I don’t know.
Answer:
pt B: (-1, -8)
Step-by-step explanation:
(x - 7)/2 = -4
x - 7 = -8
x = -1
(y-6)/2 = -7
y - 6 = -14
y = -8
Answer: It’s c
Step-by-step explanation:
