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3 years ago

Monica is buying a new dress for her

Mathematics

1 answer:

mina [271]3 years ago

7 0

Answer: Sales tax would be $5.40

Step-by-step explanation: The sales value itself of the dress (that is, without tax) is $65.49.

The amount charged as sales tax in Pearland is given as 8.25% (or 0.0825).

Hence if she is shopping in Pearland, the AMOUNT OF SALES TAX she would pay can be calculated as,

Sales tax = Sales price x 0.0825

Sales tax = 65.49 x 0.0825

Sales tax = 5.402925

Approximately to two decimal places, the sales tax becomes $5.40

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If AABC ~ AAVW, find the values of x and y.

sergey [27]

Answer:

x=28, y=12

Step-by-step explanation:

The squiggly symbol? This means the shapes/angles are congruent, meaning that if you rotated them around, they would match.

x's match runs along the same line as it's match, and same goes for y's. Imagine rotating around the lower triangle and lining it up with the upper triangle.

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3 years ago

The function rule T–4, 6(x, y) could be used to describe which translation?

RSB [31]

Answer: B

Step-by-step explanation: a trapezoid on a coordinate plane that is translated 4 units to the left and 6 units up

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3 years ago

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What is 10 1/8 + 3 5/8 2 7/8 ?

Damm [24]

So first you would have to add 10 and 1/8 and 3 and 5/8 which is 4 and 3/4 then add 2 and 7/8 to 4 and 3/4 which is 7 and 5/8 so 7 5/8 is the answer.

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2 years ago

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Which best describes the graph of g(x) = 1/9 sq x PICTURE DOWN BELOW

Alexus [3.1K]

Answer:

A) The graph of g(x) is shrunk vertically by a factor of 1/9

Step-by-step explanation:

The given graph g(x) = 1/9√x

f(x) = √x

The altitude of g(x) = 1/9

The altitude of f(X) = 1

When comparing the graph of g(x) with f(x), the graph of g(x) shrunk by 1/9 because of the altitude.

Here with I have attached the graph.

Therefore, answer: A) The graph of g(x) is shrunk vertically by a factor of 1/9

Thank you.

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3 years ago

Suppose that the mean water hardness of lakes in Kansas is 425 mg/L and these values tend to follow a normal distribution. A lim

tino4ka555 [31]

Answer:

The mean water hardness of lakes in Kansas is 425 mg/L or greater.

Step-by-step explanation:

We are given the following data set:

346, 496, 352, 378, 315, 420, 485, 446, 479, 422, 494, 289, 436, 516, 615, 491, 360, 385, 500, 558, 381, 303, 434, 562, 496

Formula:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{10959}{25} =438.36$

Sum of squares of differences = 175413.76

$S.D = \sqrt{\dfrac{175413.76}{24}} = 85.49$

Population mean, μ = 425 mg/L

Sample mean, $\bar{x}$ = 438.36

Sample size, n = 25

Alpha, α = 0.05

Sample standard deviation, s = 85.49

First, we design the null and the alternate hypothesis

$H_{0}: \mu \geq 425\text{ mg per Litre}\\H_A: \mu < 425\text{ mg per Litre}$

We use one-tailed t test to perform this hypothesis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }$

Putting all the values, we have

$t_{stat} = \displaystyle\frac{438.36 - 425}{\frac{85.49}{\sqrt{25}} } = 0.7813$

Now, $t_{critical} \text{ at 0.05 level of significance, 24 degree of freedom } = -1.7108$

Since,

The calculated t-statistic is greater than the critical value, we fail to reject the null hypothesis and accept it.

Thus, the mean water hardness of lakes in Kansas is 425 mg/L or greater.

6 0

3 years ago