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blagie [28]
3 years ago
14

You want to construct a 92% confidence interval. The correct z* to use is

Mathematics
1 answer:
Vaselesa [24]3 years ago
6 0

Answer:

1) The correct z* to to construct a 92% confidence interval is 1.75

2) these results are not good evidence that the new curriculum has improved Math SAT scores.

3) the results are not statistically significant at level α = 0.05, but they are practically significant.

Step-by-step explanation:

1) z-score for 92% confidence level is ≈ 1.75

2) P-value for testing whether the mean score in senator's state is more than the national average of 480 is less than 0.0001 means that

the probability that the sample is drawn from the population where senator's state is more than the national average of 480 is <0.0001.

Thus we have to reject this hypothesis since the probability is too small.

3) if we calculate the statistic of the sample we get (560-480)/100=0.8 where

  • 560 is the mean score of trained 4 students
  • 480 is the mean math sat score of this year
  • 100 is the standard deviation of the test.

Since t-critical at 0.05 significance for 3 degrees of freedom ≈ 2.35 is bigger than 0.8, the result is not significant statistically.

But 80 points higher than the national average is a practically significant result since its <em>effect size</em> is large.

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Answer:

  • 124 children
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Step-by-step explanation:

It usually works well to let a variable represent quantity of the highest-value contributor. Here, that is the quantity of adult tickets.

Let "a" represent the number of adult tickets sold. Then (324-a) is the number of admission fees for children. The total revenue is ...

  5.40a +2.50(324 -a) = 1390

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  2.90a = 580 . . . . . . . . . subtract 810

  a = 200 . . . . . . . . . . . . . .divide by 2.90

The number of children admitted was 124; the number of adults admitted was 200.

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3 years ago
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If a is the average (arithmetic mean) of 6m and 10, b is the average of 4m and 4, and c is the average of 14m and 16, what is th
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Answer:

6m+7.5

Step-by-step explanation:

the arithmetic mean is the average of two numbers

it is given that a is average of 6m and 10

so a=\frac{6m+10}{2}

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c is the average of 14m and 16

so c=\frac{14m+16}{2}

now the average of a ,b and c is given by

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12+2x

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2(x-4)= 2x-8

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12+2x

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