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Margaret [11]
3 years ago
10

There are 27 pupils. There are twice as many boys than girls. how many boys and girls are there

Mathematics
2 answers:
Ann [662]3 years ago
5 0
No. of boys=2x
no.of girls=x
total no. of pupils=2x+x
27=3x
27/3=x
x=no.of girls=9
no.of boys =2x=2*9=18
Anna71 [15]3 years ago
3 0
Let x  =  the numbers of girls
thus
the numbers of boys  = 2x 
x + 2x = 27
3x = 27
x = 9
2x = 2 . 9 =18
girls  =  9  &  boys  = 18
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How much money would you have if you earned 250 an hour every day?<br><br> (Easy Points)
dalvyx [7]

Answer:

I would have 360000.

Step-by-step explanation:

250 (the amount of money I earned) x 60(as in 60 mins in a hour) and 24(as in 24 hours a day) equals 360000 total.

4 0
2 years ago
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quester [9]

Answer:

The amount needed to pay off the loan after 4 years is $70,192

Step-by-step explanation:

When interest is compounded annually, total amount A after t years is given by:

A = P(1 + r)^{t}

where P is the initial amount (principal), r is the rate and t is time in years.

From the question:

P = $60,000

r = 4% = 0.04

t = 4

A = 60000(1 + 0.04)^{4} \\A = 60000(1.04)^{4}\\A = 60000 * 1.16985856\\A = 70191.5136\\A = 70192

The amount needed to pay off the loan after 4 years is $70,192

If we divide the amount by four, we will get the amount that is paid yearly (70192/4 = 17548). $17,548 is paid yearly.

7 0
3 years ago
What two numbers add up to -27 and multiply to 72?
leonid [27]
-3-24=-27, -3x-24=72
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5 0
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(c) Find (dy)/(dx) given y = ((1 + 2x)/(1 + x)) ^ 2​
hichkok12 [17]

Delete this answer please.

6 0
3 years ago
A torus is formed by rotating a circle of radius r about a line in the plane of the circle that is a distance R (&gt; r) from th
jeyben [28]

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\displaystyle2\pi\int_R^{R+2r}2xy\,\mathrm dx

where 2y=\sqrt{r^2-(x-(R+r))^2}-(-\sqrt{r^2-(x-(R+r))^2})=2\sqrt{r^2-(x-(R+r))^2}.

So the volume is

\displaystyle4\pi\int_R^{R+2r}x\sqrt{r^2-(x-(R+r))^2}\,\mathrm dx

Substitute

x-(R+r)=r\sin t\implies\mathrm dx=r\cos t\,\mathrm dt

and the integral becomes

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Notice that \sin t\cos^2t is an odd function, so the integral over \left[-\frac\pi2,\frac\pi2\right] is 0. This leaves us with

\displaystyle4\pi r^2(R+r)\int_{-\pi/2}^{\pi/2}\cos^2t\,\mathrm dt

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