No. We claim that
and use algebra to prove the statement.
Let
. Multiply this by ten to get
. Subtract the initial equation to give
and divide by
to see that
. Substituting into the original equation gives
, proving the desired statement.
Answer:
Hello! answer: y = 122
Step-by-step explanation:
360 - 116 = 244 244 ÷ 2 = 122 therefore y = 122
Hope that helps!
Answer:
a= Apple = 3
b= Banana =5
v= Lollypop=1
Step-by-step explanation:
36 is divided into 2 giving us 18
Let apple=a
Banana=b
Lollypop=c
In the first half
An apple + 3 bananas=18
a+3b=18 (1)
Second half is further divided into 2
That is,
18÷2=9
First half of the second half
3apples=9
3a=9 (2)
Second half of the second half
1 apple + 1 banana + 1 lollypop=9
a+b+c=9 (3)
a+3b=18 (1)
3a=9 (2)
a+b+c=9 (3)
From (2)
3a=9
Divide both sides by 3
a=9/3
a=3
Substitute a=3 into 1
a+3b=18
3+3b=18
3b=18-3
3b=15
Divide both sides by 3
b=15/3
=5
b=5
Substitute the value of a and b into (3)
a+b+c=9
3+5+c=9
8+c=9
c=9-8
c=1
Therefore,
a= Apple = 3
b= Banana =5
v= Lollypop=1
If we let 
be the number of pages read in 1 hour, then in 7 hours Doug reads 
pages. We know that this number of pages is 231, so we have
Part A.
The trip starts at 8am which corresponds to 0 hrs, point (0hr, 0mi)
2hrs later it's 10am. .point (2hr, 140mi)
The average speed is the slope between 0 and 2 hrs. Remember the slope formula m = Δy/Δx
m = (140 - 0) / (2 - 0)
m = 70 mph
Part B. Average speed from 11am - 2pm
11am is point (3hr, 140mi)
2pm is point (6hr, 300mi)
As you can see from the graph, the speed or slope changes at 1pm (5,260). You Can just use the start and end points.
m = (300-140) / (6-3)
m = 160/3
53.3 mph
* It comes out the same solution as if you average the two different slopes. 2hrs at 60mph + 1 hr at 40mph = (120 + 40)/3 = 160/3
Part C. Total average speed = total distance / total time driving
He went 70 mph for 2 hrs
stopped for an hour (slope is zero, no speed)
60 mph for 2hrs
40mph for 1 hr
300mi /5hr = 60mph
Part D. No Question....
