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3 years ago

Slope of (-2,-1) and (5,-1) in fraction form

Mathematics

1 answer:

dangina [55]3 years ago

7 0

Slope is 0

Step-by-step explanation:

Step 1: Find slope using the formula for slope, m = (y2 - y1)/(x2 - x1) Here, x1 = -2, y1 = -1, x2 = 5 and y2 = -1

⇒ m = (-1 - -1)/(5 - -2)

= 0/7 = 0

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A ball is thrown from a height of 105 feet with an initial downward velocity of 9 ft/s. The ball's height h (in feet) after t se

zloy xaker [14]

Answer:

t = 2.28 s

Step-by-step explanation:

h = 105 - 9t - 16t ^ 2

0 ft = 105 ft - 9t -16^t

To find the roots of a quadratic function we have to use the Bhaskara formula , the roots will give us the time it takes to reach zero height

ax^2 + bx + c = 0

-16^t - 9t + 105 ft = 0 ft

a = -16 b = -9 c = 105

t1 = (-b + √ b^2 - 4ac)/2a

t2 =(-b - √ b^2 - 4ac)/2a

t1 = (9 + √(-9^2 - (4 * (-16) * 105)))/2 * (-16)

t1 = (9 + √(-81 + 6720))/ -32

t1 = (9 + √6639)/ -32

t1 = (9 + 81.84)/ -32

t1 = 90.84 / -32

t1 = -2.83 s

t2 = (9 - √(-9^2 - (4 * (-16) * 105)))/2 * (-16)

t2 = (9 - √(-81 + 6720))/ -32

t2 = (9 - √6639)/ -32

t2 = (9 - 81.84)/ -32

t2 = -72.84 / -32

t2 = 2.28 s

we have two possible values, we are only going to take the positive one, beacause we are talking about time

t2 = 2.28 s

3 0

4 years ago

How do I solve this

In-s [12.5K]

You use lots and lots of math.

5 0

3 years ago

I’m new to this app!<br> And i really need help..<br> PLEASE HELP!!!!!

aalyn [17]

Step-by-step explanation:

a) $x^2 - 5x + 4 = (x - 1)(x - 4)$

b) $x^2 - 10x + 9 = (x - 1)(x - 9)$

c) $x^2 - 16x + 64 = (x - 8)^2$

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3 years ago

Needdd hellpppppssssssss

Ratling [72]

Answer:

Choice number one:

$\displaystyle \frac{5}{10}\cdot \frac{4}{9}$ .

Step-by-step explanation:

Let $A$ be the event that the number on the first card is even.
Let $B$ be the event that the number on the second card is even.

The question is asking for the possibility that event $A$ and $B$ happen at the same time. However, whether $A$ occurs or not will influence the probability of $B$ . In other words, $A$ and $B$ are not independent. The probability that both $A$ and $B$ occur needs to be found as the product of

the probability that event $A$ occurs, and
the probability that event $B$ occurs given that event $A$ occurs.

5 out of the ten numbers are even. The probability that event $A$ occurs is:

$\displaystyle P(A) = \frac{5}{10}$ .

In case A occurs, there will only be four cards with even numbers out of the nine cards that are still in the bag. The conditional probability of getting a second card with an even number on it, given that the first card is even, will be:

$\displaystyle P(B|A) = \frac{4}{9}$ .