Answer:
In the given figure the point on segment PQ is twice as from P as from Q is. What is the point? Ans is (2,1).
Step-by-step explanation:
There is really no need to use any quadratics or roots.
( Consider the same problem on the plain number line first. )
How do you find the number between 2 and 5 which is twice as far from 2 as from 5?
You take their difference, which is 3. Now splitting this distance by ratio 2:1 means the first distance is two thirds, the second is one third, so we get
4=2+23(5−2)
It works completely the same with geometric points (using vector operations), just linear interpolation: Call the result R, then
R=P+23(Q−P)
so in your case we get
R=(0,−1)+23(3,3)=(2,1)
Why does this work for 2D-distances as well, even if there seem to be roots involved? Because vector length behaves linearly after all! (meaning |t⋅a⃗ |=t|a⃗ | for any positive scalar t)
Edit: We'll try to divide a distance s into parts a and b such that a is twice as long as b. So it's a=2b and we get
s=a+b=2b+b=3b
⇔b=13s⇒a=23s
Answer:
13
Step-by-step explanation:
Write an equation setting the lengths equal to each other.
5x + 3 = 2x + 9
Move the variable (x) to one side. I'm going to subtract 2x from both sides.
5x - 2x + 3 = 2x - 2x + 9
3x + 3 = 9
Subtract 3 from both sides
3x +3 - 3 = 9 - 3
3x = 6
Divide both sides by 3
3x/3 = 6/3
x = 2
Now use 2x + 9 to find the length of EG by substituting 2 in for x.
2x + 9
2(2) + 9
4 + 9
13
You could also use 5x + 3 to find the length of EG by substituting 2 in for x.
The circumference is 113.04 and multiple that by 7.50 to get 847.8 and i believe that’s the answer.
Answer: 15 weeks
Step-by-step explanation:
Because there are 7 days in a week, simply divide 105/7 to get 15 weeks.
Hope it helps <3
Answer: a) 100
<u>Step-by-step explanation:</u>
Volume (V) of the prism = Length(L) x width(w) x height(h)
V = 7 x 7 x 6.5
= 318.5 cm³
Next, what is the volume of an M & M? The info isn't given so according to the internet it is 0.636 cm³
The nearest answer to this is: (a) 100
because the upper limit cannot be 10,000
