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bogdanovich [222]

3 years ago

9

What is the length of the diagonal of the triangle?

1 answer:

Setler79 [48]3 years ago

7 0

Answer:

21.25

Step-by-step explanation:

use the Pythagorean theorem, it is given that the shape is a rectangle so all opposite sides are congruent and all angles are right, since we know that the diagonal forms a right triangle we can use the pythagorean theorem

the Pythagorean theorm is a^2+b^2=c^2 where a and b are the legs (in this case the side of the triangle) and c is the hypotenuse which is the longest side in a right triangle

17^2+12.75^2=x^2

x^2=7225/16

now take the square root of both sides and you get -21.25 and 21.25

distance CAN NOT be negative so -21.25 isn't an option

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Please help me asap

just olya [345]

Answer:

3)7/12

4)2*14/25

5)25

hope my effort will help you in some way

3 0

3 years ago

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one teaspoon equals 0.5 centimeters. how many liters equals 50 teaspoons? Round the answer to the nearest hundredth.

alukav5142 [94]

50 teaspoons would equal 50*0.5 = 25 centimeters

1 cm = 0.001 liter

25*0.001 = 0.025 liters

8 0

3 years ago

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Twenty percent of drivers driving between 10 pm and 3 am are drunken drivers. In a random sample of 12 drivers driving between 1

Lesechka [4]

Answer:

(a) 0.28347

(b) 0.36909

(c) 0.0039

(d) 0.9806

Step-by-step explanation:

Given information:

n=12

p = 20% = 0.2

q = 1-p = 1-0.2 = 0.8

Binomial formula:

$P(x=r)=^nC_rp^rq^{n-r}$

(a) Exactly two will be drunken drivers.

$P(x=2)=^{12}C_{2}(0.2)^{2}(0.8)^{12-2}$

$P(x=2)=66(0.2)^{2}(0.8)^{10}$

$P(x=2)=\approx 0.28347$

Therefore, the probability that exactly two will be drunken drivers is 0.28347.

(b)Three or four will be drunken drivers.

$P(x=3\text{ or }x=4)=P(x=3)\cup P(x=4)$

$P(x=3\text{ or }x=4)=P(x=3)+P(x=4)$

Using binomial we get

$P(x=3\text{ or }x=4)=^{12}C_{3}(0.2)^{3}(0.8)^{12-3}+^{12}C_{4}(0.2)^{4}(0.8)^{12-4}$

$P(x=3\text{ or }x=4)=0.236223+0.132876$

$P(x=3\text{ or }x=4)\approx 0.369099$

Therefore, the probability that three or four will be drunken drivers is 0.3691.

(c)

At least 7 will be drunken drivers.

$P(x\geq 7)=1-P(x$

$P(x\leq 7)=1-[P(x=0)+P(x=1)+P(x=2)+P(x=3)+P(x=4)+P(x=5)+P(x=6)]$

$P(x\leq 7)=1-[0.06872+0.20616+0.28347+0.23622+0.13288+0.05315+0.0155]$

$P(x\leq 7)=1-[0.9961]$

$P(x\leq 7)=0.0039$

Therefore, the probability of at least 7 will be drunken drivers is 0.0039.

(d) At most 5 will be drunken drivers.

$P(x\leq 5)=P(x=0)+P(x=1)+P(x=2)+P(x=3)+P(x=4)+P(x=5)$

$P(x\leq 5)=0.06872+0.20616+0.28347+0.23622+0.13288+0.05315$

$P(x\leq 5)=0.9806$

Therefore, the probability of at most 5 will be drunken drivers is 0.9806.

5 0

3 years ago

While shopping for gifts, Asha bought 4 candles and 2 picture frames for $20, Jacob bought 6 candles and 1 picture frame for $18

Jobisdone [24]

Answer:

B

Step-by-step explanation:

I added all of then and then subtracted 47 from the 50.

4 0

2 years ago

Please help!! ASAP!!

ser-zykov [4K]

Answer:

The scientific notation will be Letter D

6 0

3 years ago

Read 2 more answers