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olganol [36]
3 years ago
10

Which ordered pair or pairs are solutions to the equation? Select ALL that apply.

Mathematics
1 answer:
mart [117]3 years ago
7 0

Answer:

c

Step-by-step explanation:

its c because i got 100% on the topic test

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What is the common factors of 12 and 42 also 63 and 84
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12|2 \\ 6 \ |2 \\ 3 \ |3 \\ 1 \\\\12=2^2*3 \\\\ 42|2\\21|3\\7\ |7\\1 \\\\42=2*3*7 \\\\ G.C.F(12;42)=2*3=6 \\\\\\\ 63|3 \\ 21|3 \\ 7 \ |7 \\ 1 \\\\ 63=3^2*7 \\\\ 84|2 \\ 42|2 \\ 21|3 \\ 7 \ |7 \\ 1 \\\\ 84=2^2*3*7 \\\\ G.C.F(63;84)=3*7=21
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How do you solve this 5b-28>27
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Five pencils and 4 erasers cost $7.65. Four pencils and 5 erasers cost $7.20.What is the cost of 2 erasers?
Arturiano [62]

I think this is right.. I tried my best. If u get it sorry... I’m very sorry



1. Divide 7.20 by 4 since the 4 are the pencils

2.divide 7.20 by 5 ( 5 represents the erasers )

3. Then finally multiply 1.44 from 7.20/5 and
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3 years ago
Find all solutions to the equation. cos^2x + 2 cos x + 1 = 0
Black_prince [1.1K]

Answer:

x = pi, 3pi, 5pi  etc

x = -pi, -3pi, -5pi etc

Step-by-step explanation:

cos^2 x + 2 cos x + 1 = 0

replace cos x with m

m^2 + 2m +1 = 0

solve by factoring  (this is a^2 +2ab+b^2 = (a+b)^2  where a =m and b=1)

(m+1)^2=0

take the square root of each side

m+1 =0

m=-1

now replace m with cos x

cos x = -1

take arccos  of each side

arccos cos x = arccos (-1)

x = pi, 3pi, 5pi  etc


3 0
3 years ago
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