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olganol [36]
3 years ago
10

Which ordered pair or pairs are solutions to the equation? Select ALL that apply.

Mathematics
1 answer:
mart [117]3 years ago
7 0

Answer:

c

Step-by-step explanation:

its c because i got 100% on the topic test

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the triglyceride levels of residents of an assisted living facility are recordered the levels are normally distributed with a me
Svet_ta [14]

Answer:

Step-by-step explanation:

P(200<X<275)

P(200-200/50 <X< 275-200/50)

P(0/50 <X< 75/50)

P(0<X<1.5)

P(X<1.5) -P(X>0)

0.9332-0.5 = 0.4332

4 0
3 years ago
Read 2 more answers
The box plots show the data distributions for the number of customers who used a coupon each hour during a two-day
algol13

Answer:

The correct answer is A: Interquartile range

Step-by-step explanation:

Just took the test and this was the correct answer

3 0
3 years ago
The number of people in thousands who own a cell phone is a function of the time in years starting in 1990 where p(t) = 20(1.075
Julli [10]
Try to look it up tbh
4 0
3 years ago
In an arithmetic sequence, a17 = -40 and
Viktor [21]

Answer:

Tn = 2Tn-1 - Tn-2

Step-by-step explanation:

Before we can generate the recursive sequence, we need to find the nth term of the given sequence.

nth term of an AP is given as:

Tn = a+(n-1)d

If a17 = -40

T17 = a+(17-1)d = -40

a+16d = -40 ...(1)

If a28 = -73

T28 = a+(28-1)d = -73

a+27d = -73 ...(2)

Solving both equations simultaneously using elimination method.

Subtracting 1 from 2 we have:

27d - 16d = -73-(-40)

11d = -73+40

11d = -33

d = -3

Substituting d = -3 into 1

a+16(-3) = -40

a - 48 = -40

a = -40+48

a = 8

Given a = 8, d = -3, the nth term of the sequence will be

Tn = 8+(n-1) (-3)

Tn = 8+(-3n+3)

Tn = 8-3n+3

Tn = 11-3n

Given Tn = 11-3n and d = -3

Tn-1 = Tn - d... (3)

Tn-1 = 11-3n +3

Tn-1 = 14-3n

Tn-2 = Tn-2d...(4)

Tn-2 = 11-3n-2(-3)

Tn-2 = 11-3n+6

Tn-2 = 17-3n

From 3, d = Tn - Tn-1

From 4, d = (Tn - Tn-2)/2

Equating both common difference

(Tn - Tn-2)/2 = Tn - Tn-1

Tn - Tn-2 = 2(Tn - Tn-1)

Tn - Tn-2 = 2Tn-2Tn-1

2Tn-Tn = 2Tn-1 - Tn-2

Tn = 2Tn-1 - Tn-2

The recursive formula will be

Tn = 2Tn-1 - Tn-2

5 0
3 years ago
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A seamstress has 1/4 of a foot of thread. Then she uses 1/5 of a foot of thread to sew a hole. How much of the thread is left?
Ilya [14]
Answer is <span>C) 1/20 of a foot

1/4 -1/5
= 5/20 - 4/20
=1/20</span>
3 0
3 years ago
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