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Oksi-84 [34.3K]
3 years ago
12

An electric train is moving north at 100mph and a wind is blowing to the west at 10mph. Which way does the smoke blow?

Mathematics
2 answers:
Gnesinka [82]3 years ago
5 0
Hope this helps you ;)

inna [77]3 years ago
4 0

Hey!

Hope this helps...

~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Okay... so we know that the train is moving north, which means the Apposing wind (and Friction) would be coming from the south.

We also know that the wind is coming from the West.

And based upon this information, we know that the Smoke has to be going South West because when an Apposing wind is pushed by a natural wind, the object being affected by both winds moves in both directions (a.k.a. diagonal)...

-----------

If you need to explain anything, please ask, I also recommend looking at the photo I made below...

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Answer:

x = 65°

Step-by-step explanation:

these are vertical angles, which are congruent

145 = 2x + 15

130 = 2x

65 = x

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At a yard sale, Celia bought an electric for 85% of its original value. Celia pad $75.65 for the guitar. What was the original v
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75.65 \div .85
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Find the value of x, y, and z in the rhombus below.
marin [14]

Consecutive angles in a paralleogram have sum 180

\\ \rm\rightarrowtail 5z+4+86=180

\\ \rm\rightarrowtail 5z+90=180

\\ \rm\rightarrowtail 5z=90

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And

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And

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5 0
2 years ago
Select the correct answer from each drop-down menu.
Harlamova29_29 [7]

According to the Alternate Exterior Angles Theorem if a pair of Parallel lines are intersected by a transversal(t) then the alternate exterior angle are congurent.-<u>Alternate Exterior Angles theorem and Linear Pair theorem</u>

<u></u>

Step-by-step explanation:

Alternate exterior angles are said to be those angles  that are outside the "block" which is  formed by the parallel lines and are placed on the  opposite sides of the transversal(t)  

From the question we can say that both  ∠2 and ∠7 are outside the parallel lines and  ∠2 is on the right side of the transversal (t) and ∠7 is on the left side of the transversal. <u>This makes ∠2 and ∠7  alternate exterior angles.</u>

<u>A linear pair is referred to as a pair of angles that are formed  from a straight line. When  ∠7 and ∠8 combined together they form a straight line this makes them a linear pair.</u>

<u></u>

<u></u>

<u>According to the  Alternate Exterior Angles Theorem if a pair of Parallel lines are intersected by a transversal(t) then the alternate exterior angle are congurent. Hence both Alternate Exterior Angles theorem and Linear Pair theorem is applicable</u>

<u></u>

8 0
3 years ago
Read 2 more answers
2. When Joey dives off a diving board, the equation of his pathway can be modeled by h = -16- + 15 + 12.
Sergeu [11.5K]

Answer:

a) The maximum height is approx 15.5 unit.

b) The time it will take for Joey to reach the water is 1.45 hour.

Step-by-step explanation:

Given : When Joey dives off a diving board, the equation of his pathway can be modeled by h(t)= -16t^2+15t + 12

To find : a) Find Joey's maximum height.

b) Find the time it will take for Joey to reach the water.

Solution :

Modeled  h(t)= -16t^2+15t + 12 ....(1)

a) To find maximum height

Derivate (1) w.r.t. t,

h'= -32t+15

For critical point put h'=0,

-32t+15=0

t=\frac{15}{32}

t=0.46875

Derivate again w.r.t. t,

h''= -32

It is maximum at t=0.46875.

Substitute t in equation (1),

h(0.46875)= -16(0.46875)^2+15(0.46875)+12

h(0.46875)= -3.515625+7.03125+12

h(0.46875)= 15.515625

The maximum height is approx 15.5 unit.

b) To find the time it will take for Joey to reach the water.

Put h=0 in equation (1),

-16t^2+15t + 12=0

Apply quadratic formula, x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

Here, a=-16 , b=15, c=12

t=\frac{-15\pm\sqrt{(15)^2-4(-16)(12)}}{2(-16)}

t=\frac{-15\pm\sqrt{225+768}}{-32}

t=\frac{-15\pm\sqrt{993}}{-32}

t=\frac{-15+\sqrt{993}}{-32},\frac{-15-\sqrt{993}}{-32}

t=−0.515,1.453

Reject negative value.

The time is t=1.45.

The time it will take for Joey to reach the water is 1.45 hour.

5 0
4 years ago
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