The last one (0,0) the middle of the graph is always (0,0)
Given :
A particle moves in the xy plane starting from time = 0 second and position (1m, 2m) with a velocity of v=2i-4tj .
To Find :
A. The vector position of the particle at any time t .
B. The acceleration of the particle at any time t .
Solution :
A )
Position of vector v is given by :

B )
Acceleration a is given by :

Hence , this is the required solution .
2x divided by -24 and -3y divided by -24 then find ur X and Y
<span>(−3, 0) and (0, 6)
Each of these work in both equations</span>
Basically they're both equal
4x-3=x+7
-x. -x
3x-3=7
+3 +3
3x=10
X=10/3