Multiply<span> by </span><span><span>(7−4i)/</span><span>(7−4i)</span></span><span> to make the </span>denominator<span> of </span><span><span>(4−7i)/</span><span>(7+4i)</span></span><span> real.
</span><span>(<span><span>4−7i/</span><span>7+4i</span></span>)(<span><span>7−4i/</span><span>7−4i</span></span>)
</span>Expand <span>(7+4i)(7−4i)</span><span> using the </span>FOIL<span> Method.
</span><span>(4−7i)(7−4i)/</span><span>7(7)+7(−4i)+4i(7)+4i(−4i<span>)
</span></span><span>Simplify.
</span><span><span>(4−7i)(7−4i)/</span>65
</span>Expand <span>(4−7i)(7−4i)</span><span> using the </span>FOIL<span> Method.
</span><span><span>4(7)+4(−4i)−7i(7)−7i(−4i)/</span>65
</span>Simplify each term<span>.
</span><span><span>28−16i−49i−28/</span>65
Simplify
</span><span><span>−65i/</span>65
</span><span>−i</span>
6z - z^6
Since we don't have the value for z, we cannot solve the expression, however, we can get out most simple expression.
Answer: 5z^6
Answer:
Step-by-step explanation:
Answer:
1.46 x 10⁶g
Step-by-step explanation:
Given parameters:
Weight of each bowling ball = 7.3 x 10³g
Number of balls in the bowling alley = 2.0 x 10²bowling balls
Unknown
The weight of the balls in the alley = ?
Solution:
To find the weight of the balls in the alley, multiply the mass of each balls with the total number of balls;
Weight of the balls = 7.3 x 10³ x 2.0 x 10²
Weight of the balls = (7.3 x 2.0) x 10³⁺²
Weight of the balls = 14.6 x 10⁵g
Therefore, the weight of the balls = 1.46 x 10⁶g
Answer:
17 + 23 = 40
23 - 17 = 6 the other person did it right.
