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Darina [25.2K]
2 years ago
14

SOMEBODY HELP MEEE!!!!

Mathematics
1 answer:
VladimirAG [237]2 years ago
8 0
Solution= x=5
Alernative form= 21 x - 105= 0<span />
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4x-10=30<br> 2n-7=30 <br> S/3+2=4
emmasim [6.3K]

Answer:

x=10 n=18.5 s=6

Step-by-step explanation:

4x-10=30

Add 10 to both sides

4x-10+10=30+10

4x=40

Divide by 4 on both sides

(4x)/4=40/4

x=10

2n-7=30

Add 7 to both sides

2n-7+7=30+7

2n=37

Divide by 2 on both sides

(2n)/2=37/2

n=18.5

(s/3)+2=4

Subtract 2 from both sides

(s/3)+2-2=4-2

(s/3)=2

Multiply by 3 on both sides

3s/3=2*3

s=6

6 0
3 years ago
The student council is hosting a drawing to raise money for scholarships. They are selling tickets for $9 each and will sell 500
ryzh [129]

Answer:

-$2.32

Step-by-step explanation:

Give that

The selling price per ticket is $9

And the number of tickets sold is 500

So,

There is one grand prize, three $300 second prize, and eleven $40 third prizes

We need to find out the expected value of the profit

= \frac{1}{500} \times 2000 +  \frac{3}{500} \times 300 + \frac{11}{500} \times 40\\\\

= 4 + 1.8 + 0.88

= 6.68

Now the expected profit is

= $6.68 - $9

= -$2.32

6 0
2 years ago
In an arithmetic sequence, a17 = -40 and
Viktor [21]

Answer:

Tn = 2Tn-1 - Tn-2

Step-by-step explanation:

Before we can generate the recursive sequence, we need to find the nth term of the given sequence.

nth term of an AP is given as:

Tn = a+(n-1)d

If a17 = -40

T17 = a+(17-1)d = -40

a+16d = -40 ...(1)

If a28 = -73

T28 = a+(28-1)d = -73

a+27d = -73 ...(2)

Solving both equations simultaneously using elimination method.

Subtracting 1 from 2 we have:

27d - 16d = -73-(-40)

11d = -73+40

11d = -33

d = -3

Substituting d = -3 into 1

a+16(-3) = -40

a - 48 = -40

a = -40+48

a = 8

Given a = 8, d = -3, the nth term of the sequence will be

Tn = 8+(n-1) (-3)

Tn = 8+(-3n+3)

Tn = 8-3n+3

Tn = 11-3n

Given Tn = 11-3n and d = -3

Tn-1 = Tn - d... (3)

Tn-1 = 11-3n +3

Tn-1 = 14-3n

Tn-2 = Tn-2d...(4)

Tn-2 = 11-3n-2(-3)

Tn-2 = 11-3n+6

Tn-2 = 17-3n

From 3, d = Tn - Tn-1

From 4, d = (Tn - Tn-2)/2

Equating both common difference

(Tn - Tn-2)/2 = Tn - Tn-1

Tn - Tn-2 = 2(Tn - Tn-1)

Tn - Tn-2 = 2Tn-2Tn-1

2Tn-Tn = 2Tn-1 - Tn-2

Tn = 2Tn-1 - Tn-2

The recursive formula will be

Tn = 2Tn-1 - Tn-2

5 0
2 years ago
Read 2 more answers
Solve for x. -2(16 - 4x) - 8 = 6(x + 2)
VARVARA [1.3K]
-32 + 8x - 8 = 6x + 12
8x - 40 = 6x + 12
8x = 6x + 12 + 40
8x = 6x + 52
8x - 6x = 52
2x = 52
x = 52/2
x = 26
3 0
2 years ago
Which graph represents a function with a growth factor of 5
mr Goodwill [35]

Answer:

the answer should be C!


Step-by-step explanation:

When you multiply the y value 0.04 and 5 it comes out as 0.02.


6 0
3 years ago
Read 2 more answers
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