Write an equation to model the problem containing an unknown number. Fifteen is the quotient of a number and three. = n ÷
2 answers:
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Answer:
5, x = 0, y = -2
6, x = 4, Y = 9
7, X = -2, Y = -2
Step-by-step explanation:
The table in the attached figure
<span>Pennies made before 1983
</span>Part a) find the mean
we have
[3.1047,3.1082, 3.1582, 3.0776, 3.1276, 3.1035]
Mean 1=[3.1047+3.1082 + 3.1582 + 3.0776 + 3.1276 + 3.1035]/6
Mean 1=3.1133 grams
the answer part a) is
The mean weight of the pennies made before 1983 is 3.1133 grams.
Part b)
to find the Median, place the numbers in value order and find the middle.
[3.1047,3.1082, 3.1582, 3.0776, 3.1276, 3.1035]
[3.0776, 3.1035, 3.1047,3.1082, 3.1276, 3.1582]
(3.1047+3.1082)/2=3.10645 grams
the answer part b) is
The median weight of the pennies made before 1983 is 3.10645 grams.
<span>Pennies made after 1983
</span>Part c) find the mean
we have
[2.4842, 2.4828, 2.5024, 2.4997, 2.4907, 2.4956]
Mean 2=[2.4842 + 2.4828 + 2.5024 + 2.4997 + 2.4907 + 2.4956]/6
Mean 2=2.4926 grams
the answer part c) is
The mean weight of the pennies made after 1983 is 2.4926 grams.
Part d)
to find the Median, place the numbers in value order and find the middle
[2.4842, 2.4828, 2.5024, 2.4997, 2.4907, 2.4956]
[2.4828, 2.4842, 2.4907, 2.4956, 2.4997, 2.5024]
[2.4907 +2.4956]/2=2.49315
the answer part d) is
The median weight of the pennies made after 1983 is 2.49315<span> grams.
</span>
Part e) compare the means
<span>Find the percentage difference
</span> the percentage difference is the difference between the new value and the old value, divided by the old value
so
new value=2.4926 grams
old value=3.1133 grams
[3.1133-2.4926]/3.1133------> 0.20-----> 20%
that means
<span>the difference in the means is considerable to be greater than 5%</span>
<span>Pennies made before 1983
</span>Part a) find the mean
we have
[3.1047,3.1082, 3.1582, 3.0776, 3.1276, 3.1035]
Mean 1=[3.1047+3.1082 + 3.1582 + 3.0776 + 3.1276 + 3.1035]/6
Mean 1=3.1133 grams
the answer part a) is
The mean weight of the pennies made before 1983 is 3.1133 grams.
Part b)
to find the Median, place the numbers in value order and find the middle.
[3.1047,3.1082, 3.1582, 3.0776, 3.1276, 3.1035]
[3.0776, 3.1035, 3.1047,3.1082, 3.1276, 3.1582]
(3.1047+3.1082)/2=3.10645 grams
the answer part b) is
The median weight of the pennies made before 1983 is 3.10645 grams.
<span>Pennies made after 1983
</span>Part c) find the mean
we have
[2.4842, 2.4828, 2.5024, 2.4997, 2.4907, 2.4956]
Mean 2=[2.4842 + 2.4828 + 2.5024 + 2.4997 + 2.4907 + 2.4956]/6
Mean 2=2.4926 grams
the answer part c) is
The mean weight of the pennies made after 1983 is 2.4926 grams.
Part d)
to find the Median, place the numbers in value order and find the middle
[2.4842, 2.4828, 2.5024, 2.4997, 2.4907, 2.4956]
[2.4828, 2.4842, 2.4907, 2.4956, 2.4997, 2.5024]
[2.4907 +2.4956]/2=2.49315
the answer part d) is
The median weight of the pennies made after 1983 is 2.49315<span> grams.
</span>
Part e) compare the means
<span>Find the percentage difference
</span> the percentage difference is the difference between the new value and the old value, divided by the old value
so
new value=2.4926 grams
old value=3.1133 grams
[3.1133-2.4926]/3.1133------> 0.20-----> 20%
that means
<span>the difference in the means is considerable to be greater than 5%</span>
1) Lets say there is point A that is perpendicular to WX and has W in it.
2) To find YA, we have to 19 - 11 = 8
3) Do Pythagorean theorem to find WY, which is:
This is equal to 42.76 in decimal
2) To find YA, we have to 19 - 11 = 8
3) Do Pythagorean theorem to find WY, which is:
This is equal to 42.76 in decimal