How could a compass be used to determine if two segments are the same length?
1 answer:
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The shop sold 36 sundaes and 28 banana spilts
<em><u>Solution:</u></em>
Let "a" be the number of sundaes sold
Let "b" be the number of banana spilts sold
Cost of 1 sundaes = $ 2
Cost of 1 banana spilt = $ 3
<em><u>On a hot summer day, the shop sold 8 more sundaes than banana splits and made $156</u></em>
Therefore,
Number of sundaes sold = 8 + number of banana spilts sold
a = 8 + b ------- eqn 1
<em><u>Also, given that they made $ 156</u></em>
<em><u>Therefore, we frame a equation as</u></em>:
Number of sundaes sold x Cost of 1 sundaes + number of banana spilts sold x Cost of 1 banana spilt = 156
2a + 3b = 156 ---------- eqn 2
<em><u>Substitute eqn 1 into eqn 2</u></em>
2(8 + b) + 3b = 156
16 + 2b + 3b = 156
16 + 5b = 156
5b = 156 - 16
5b = 140
<h3>b = 28</h3><em><u>Substitute b = 28 in eqn 1</u></em>
a = 8 + 28
<h3>a = 36</h3>Thus the shop sold 36 sundaes and 28 banana spilts
Answer:
No. Remember, a right angle must have a 90 degree angle. We can find the lengths with the Pythagorean Theorem.
Step-by-step explanation:
Given the length 7, 10, and 12, we can assume that 12 is the hypotenuse (it is the longest length).
- we can use 7 and 10 interchangeably.
Fill in the equation,
where c = 12, and a or b = 7 or 10.
To indicate if the given lengths would form a right angle, we can only input 7 or 10, not both.
Therefore, or
==> 49 + b^2 = 144 ==> <u>b= </u>
<u> ==> </u><u>9.746</u>
b= 9.7, not 10.
==> 100 + b^2 = 144 ==> <u>b = </u>
<u> ==> </u><u>6.633 </u>
b= 6.6, not 7.
Therefore, the lengths 7, 10, and 12, does NOT make a right triangle.
Hope this helps!