Hello,
Let's place the last digit: it must be 2 or 4 or 8 (3 possibilities)
It remainds 4 digits and the number of permutations fo 4 numbers is 4!=4*3*2*1=24
Thus there are 3*24=72 possibilities.
Answer A
If you do'nt believe run this programm
DIM n(5) AS INTEGER, i1 AS INTEGER, i2 AS INTEGER, i3 AS INTEGER, i4 AS INTEGER, i5 AS INTEGER, nb AS LONG, tot AS LONG
tot = 0
n(1) = 1
n(2) = 2
n(3) = 4
n(4) = 7
n(5) = 8
FOR i1 = 1 TO 5
FOR i2 = 1 TO 5
IF i2 <> i1 THEN
FOR i3 = 1 TO 5
IF i3 <> i2 AND i3 <> i1 THEN
FOR i4 = 1 TO 5
IF i4 <> i3 AND i4 <> i2 AND i4 <> i1 THEN
FOR i5 = 1 TO 5
IF i5 <> i4 AND i5 <> i3 AND i5 <> i2 AND i5 <> i1 THEN
nb = ((((n(i1) * 10) + n(i2)) * 10 + n(i3)) * 10 + n(i4)) * 10 + n(i5)
IF nb MOD 2 = 0 THEN
tot = tot + 1
END IF
END IF
NEXT i5
END IF
NEXT i4
END IF
NEXT i3
END IF
NEXT i2
NEXT i1
PRINT "tot="; tot
END
The answer to A is the pic below
Answer:(
(1,0),(-3,0)
Step-by-step explanation:
For the regression equation and e the number of kilowatt-hours, in thousands, for a six-room house is mathematically given as
Y = 1.33-0.667X and 5.3332
<h3>What is the number of kilowatt-hours, in thousands, for a six-room house?</h3>
Generally, the equation for the standard deviation is mathematically given as
ₓ =
= 
= 2.72
= 
= 2.01
therefore correlation coff
r = 
r = 0.9038
In conclusion the regression equation is given
b = r_sy/sx
b = (0.9038)(2.01/2.72)
= 0.667
intercept
a = 7.4-0.667(9.1)
a = 1.33
The regression equation is
Y = 1.33-0.667X
(b) number of kilowatts x = 6 house
Y = 1.33-0.667X
Y = 1.33-0.667(6)
= 5.3332
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