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4 years ago

Help me pls I really really need help with this I'm so bad at math

Mathematics

1 answer:

MAVERICK [17]4 years ago

6 0

Question 7: Answer J (7/8 - 1/2 = 3/8)

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Work out the gradient of a line that passes through co-ordinates (3,4) & (6,16).

Ipatiy [6.2K]

Answer:

4.33

Step-by-step explanation:

Given data

x1= 3

y1=3

x2=6

y2=16

M= y2-y1/x2-x1

substitute

M=16-3/6-3

M= 13/3

M=4.33

Hence the gradient is 4.33

3 0

3 years ago

What is the area of the circle? d = 8 m 6471 m2 50.24 m2 100.48 m2

Zarrin [17]

Answer: 50.24 m2

Step-by-step explanation:

the fomlua for the area of a cuculal is

A=1/4 π d^2

so...

1/4 * π * 8^2

=50.24

7 0

3 years ago

Help 7th grade work I’ll brainlist

lukranit [14]

Answer:

I need help too

Step-by-step explanation:

someone please

5 0

3 years ago

The surface area of a rectangular prism is 2210 cm2. Two of the dimensions are 5 cm and 10 cm. Find the measure of the other dim

Vlad [161]

The surface area of a rectangular prism is 2210 cm^2 Then the other dimension is 70.3 cm

<h3>Solution:</h3>

Given that surface area of rectangular prism is 2210 square centimeter

Also given that two of dimensions are 5 cm and 10 cm

To find: other dimension

The total surface area of the rectangular prism is gievn as:

$\text {Total surface area }=2(lb+b h+h l)$

Where, "l" is the length and "b" is the breadth and "h" is the height

The given values are: l = 5cm and b = 10cm

On substituting the given values in formula we get,

$\begin{array}{l}{2210=2(l \times b+b \times h+h \times l)} \\\\ {2210=2(5 \times 10+10 \times h+h \times 5)} \\\\ {2210=2(50+10 h+5 h)} \\\\ {1105=50+15 h} \\\\ {1055=15 h} \\\\ {h=70.3}\end{array}$

Thus the other dimension is 70.3 cm

6 0

4 years ago

Find the distance between each pair of points. Leave your answers in simplest radical form.

Oksanka [162]

The formula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

1. (6, 8), (5, 5). Substitute:

$d=\sqrt{(5-6)^2+(0-8)^2}=\sqrt{(-1)^2+(-8)^2}=\sqrt{1+64}=\sqrt{65}$

2. (-3, -2), (-5, 3). Substitute:

$d=\sqrt{(-5-(-3))^2+(3-(-2))^2}=\sqrt{(-2)^2+5^2}=\sqrt{4+25}=\sqrt{29}$

4 0

3 years ago