Question

Please help me compute 5 P2a. 20b. 10c. 3d. 2.5

Answer 1

Formula: $_nP_r= \dfrac{n!}{(n-r)!}\)$

n = 5 , r = 2

$_5P_2=\dfrac{5!}{(5-2)=3!}\)$

$\(\dfrac{5!=5*4*3*2*1}{3!=3*2*1}=\dfrac{5*4}{1}=5*4=20\)$