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Gala2k [10]
3 years ago
13

The record high temperature in January was 18 degrees. The record low temperature was –7 degrees. What is the amount of change b

etween the high and low temperatures
Mathematics
1 answer:
vodka [1.7K]3 years ago
6 0

Answer: 25^{\circ}

Step-by-step explanation:

Given

The highest temperature recorded is 18^{\circ}

The lowest temperature recorded is -7^{\circ}

The amount of change between the high and the low temperatures is

\Rightarrow 18-(-7)=18+7\\\Rightarrow 25^{\circ}

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Remember that you can do anything to an equation as long as you do it to both sides except divide by zero
so you can add like terms like this
you can add similar things like 1+3 and m+2m and m^2+2m^2 but not unlke things like 1+m or m+m^2

so m+2m=1m+2m=3m so

r-4+6r=3+8r
use commutative property to move numbers around (a+b=b+a)
group like terms
r+6r-4=3+8r
add like terms
1r+6r-4=3+8r
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How much time is needed for $1,800 to accumulate $360 in simple interest at a rate of 10%?
Fiesta28 [93]
I = PRT....rearrange
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<h3><u>Ⲁⲛ⳽ⲱⲉⲅ</u><u>:</u></h3>

\quad\hookrightarrow\quad \sf {5,790,806.5\:ft^3 }

<h3><u>Ⲋⲟⳑⳙⲧⳕⲟⲛ:</u></h3>

Here, we area provided a cone with:

  • Radius = 48m
  • Height = 68 m

We have to find the volume of the cone in feet³, and we are given that 1m = 3.2808ft

<h3><u>Ⳙ⳽ⲓⲛⳋ ⳨ⲟⲅⲙⳙ</u><u>ⳑɑ</u><u>:</u></h3>

The volume of a cone is equal to one third of the volume of a cylinder having the same base radius and height ,i.e:

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\implies\quad \tt { V =\dfrac{1}{\cancel{3}}\times 3.14\times \cancel{2304} \times 68}

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\implies\quad \tt {V = 163,983.36\times 35.30 }

\implies\quad\underline{\pmb{ \tt { V = 5,790,806.5 ft^3}}}

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Answer:

Let's simplify step-by-step.

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Answer:=−x−4

Step-by-step explanation:

answer:-4

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