We want to find the probability that the two students chosen for the duet are boys. We will find that the probability that both students chosen for the duet are boys is 0.458
If we assume that the selection is totally random, then all the students have the same<em> </em><em>probability </em><em>of being chosen.</em>
This means that, for the first place in the duet, the probability of randomly selecting a boy is equal to the quotient between the number of boys and the total number of students, this is:
P = 11/16
For the second member of the duet we compute the probability in the same way, but this time there is one student less and one boy less (because one was already selected).
Q = 10/15
The joint probability (so both of these events happen together) is just the product of the individual probabilities, this will give:
Probability = P*Q = (11/16)*(10/15) = 0.458
So the probability that both students chosen for the duet are boys is 0.458
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Answer:

Step-by-step explanation:

Multiply the row of the first matrix to the column of the second matrix





simplifying them we get

Answer:

Step-by-step explanation:
If the point (2,3) is on the terminal side of an angle in standard position.
Adjacent of O, x=2,
Opposite of O, y=3
Next, we determine the hypotenuse, r using Pythagoras Theorem.

Therefore:



Answer:
y = -3/4x + 3
Step-by-step explanation:
y - 9 = -3/4 (x-8)
y-9 = -3/4x -6
y = -3/4x - 6 + 9
y = -3/4x + 3
hope this helps if not sorry
One complete revolution of the minute hand sweeps a central angle of 360° which is equivalent to 60 minutes.
That is, the minute hand creates
(360°/(60 min) = 6 degrees/min.
From 3:35 to 3:55 is 20 minutes.
It sweeps a central angle of
(20 min)*(6 deg/min) = 120°
Because 360° = 2π radians,
120° = (120/360)*2π = (2π)/3 radians
Answer:

In decimals, this is 2.1 radians (nearest tenth)
Part 2:
Because the minute hand is 4 inches long, the length of the arc swept is
(4 in)*(2π/3 radians) = 8π/3 inches
Answer:

In decimals, this is 8.4 inches (nearest tenth).