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3 years ago

For the function y=-2+5sin(pi/12)(x-2) what is the maximum value

Mathematics

1 answer:

alexira [117]3 years ago

5 0

The maximum value of the sine function is 1. Therefore the maximum value of y is:
y(max) = -2 + 5 = 3

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A. (–2, –3)

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3 years ago

A student is decorating a circular picture frame that has a diameter of 8 inches. How many inches of fabric will the student nee

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3 years ago

A junk box in your room contains fourteen old batteries, seven of which are totally dead. You start picking batteries one at a

MrMuchimi

Answer:

A junk box in your room contains fourteen old batteries, seven of which are totally dead.

So, number of good batteries = $14-7=7$

a) The first two you choose are both good.

There is a 7/14 chance that we will pick a good battery.

Now there are 13 batteries left and out of that there are only 6 good ones remaining, so this becomes 6/13.

So, combined probability is = $\frac{7}{14}\times \frac{6}{13}$

= 0.23

b) At least one of the first three works.

$\frac{7}{14} \times \frac{6}{13} \times \frac{5}{12} =0.096$

And at least one is good battery, we get : $1-0.096=0.904$

c) The first four you pick all work.

There is a probability of 7/14 for the first one to work, 6/13 for the second, 5/12 for the third and 4/11 when the fourth is good, combined we get by multiplying all:

$\frac{7}{14}\times \frac{6}{13}\times \frac{5}{12}\times \frac{4}{11}=0.0344$

d) You have to pick five batteries to find one that works.

This condition means that we pick 4 bad batteries and 1 good battery.

The probability of picking 4 bad batteries is -

$\frac{7}{14}\times \frac{6}{13}\times \frac{5}{12}\times \frac{4}{11}=0.0344$

Since there are 7 good batteries remaining in 10 batteries so we will multiply 7/10 in 0.0344 to know the fifth one that finally works.

This becomes = $0.0344\times0.7=0.024$

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3 years ago