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drek231 [11]
3 years ago
7

For the function y=-2+5sin(pi/12)(x-2) what is the maximum value

Mathematics
1 answer:
alexira [117]3 years ago
5 0
The maximum value of the sine function is 1. Therefore the maximum value of y is:
y(max) = -2 + 5 = 3
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Is x - 8 a factor of the function f(x) = -2x3 + 17x2 - 64? Explain.
Oduvanchick [21]

we know that

If (x-8) is a factor of the function f(x)=-2x^{3}+17x^{2}-64

then

x=8 is a root of the function f(x)

therefore

For x=8 the value of the function must be zero

Verify

Substitute the value of x=8 in the function

f(8)=-2(8)^{3}+17(8)^{2}-64

f(8)=-2(512)+17(64)-64

f(8)=-1,024+1,088-64

f(8)=-1,088+1,088

f(8)=0

therefore

<u>the answer is</u>

Yes, (x-8) is a factor of the function f(x)

7 0
3 years ago
Read 2 more answers
Find the value of x. No calculator needed. Leave the square root as a part of your answer.
aleksklad [387]

Answer:

5/V2=2.5×V2

Step-by-step explanation:

This is an isoscelle right triangle:

x²+x²=5²

2x²=5²

x=5/V2=5×V2/2=2.5×V2

where V2=sqrt(2)

4 0
3 years ago
2. Kim is x years old. Jordan is 7 years older than Kim. Four times Jordan’s age is equal to 200.
Shkiper50 [21]
Kim is X 
Jordan= x+7
So J x 4=200

This means 4(x+7) = 200
x=43
43+7=50
50 x 4=200

so Kim is 43 and Jordan is 50.
4 0
3 years ago
The volume of a box is 80 cubic feet with length x-3 and width x-1 and height x+5. What are the possible values of x? What are t
Kryger [21]

Answer:

  • the only possible value of x is 5
  • the dimensions are 2 × 4 × 10

Step-by-step explanation:

The cubic equation ...

  (x -3)(x -1)(x +5) = 80

has one real root: x = 5. Using that value for x, the dimensions become ...

  length = 5 - 3 = 2

  width = 5 - 1 = 4

  height = 5 + 5 = 10

The dimensions are (length, width, height) = (2, 4, 10).

_____

We cannot tell the thrust of the problem, since it has only one solution. Perhaps you're supposed to write the cubic in standard form and use the <em>Rational Root theorem</em> to find <em>possible values of x</em>. That form can be found to be ...

  (x -3)(x -1)(x +5) -80 = 0

  x³ +x² -17x -65 = 0

Descartes' rule of signs tells you there is one positive real root. The rational root theorem tells you possible rational roots are factors of 65:

  1, 5, 13, 65

We know that x must be greater than 3 (so all dimensions are positive). Thus <em>possible values of x are 5, 13, 65</em>, and we're pretty sure that 65 is way too large.

4 0
3 years ago
ASAP plz answers just
faust18 [17]

Answer:

<em>(a) x(x+2)  (b) 2x(x-3)  (c) 5x(3-2x^2)  (d) 3x^2(3+x)</em>

Step-by-step explanation:

For each expression, <u>we need to factor out the GCF(Greatest common factor)</u>

a)   x^2+2x

Here, the GCF is  x. So, we will get.....

x^2+2x\\ \\ =x(\frac{x^2}{x}+ \frac{2x}{x}) \\ \\ =x(x+2)

b)   2x^2-6x

Here, the GCF is  2x. So, we will get......

2x^2-6x\\ \\ =2x(\frac{2x^2}{2x}- \frac{6x}{2x}) \\ \\ =2x(x-3)

c)   15x-10x^3

Here, the GCF is  5x. So, we will get.......

15x-10x^3\\ \\ =5x(\frac{15x}{5x}- \frac{10x^3}{5x}) \\ \\ =5x(3-2x^2)

d)   9x^2+3x^3

Here, the GCF is  3x^2. So, we will get.......

9x^2+3x^3\\ \\ =3x^2(\frac{9x^2}{3x^2}+ \frac{3x^3}{3x^2}) \\ \\ =3x^2(3+x)

8 0
3 years ago
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