the answer is A because restriction enzymes function in cutting strand of DNA at specufic sites
After 10 years, the isotope would have had two half lives. For each half life, half of the material reacts. Therefore, after one half life, 50% remains. Then, after a second, 25% remains. D is the correct answer.
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The process of fusing two or more DNA molecules to produce a hybrid is known as recombinant DNA. Restrictions endonucleases and ligases are two classes of enzymes that enable the technique.
When a restriction endonuclease detects a particular DNA sequence, it makes cuts inside or near that sequence. The recognition sequence of a restriction enzyme will haphazardly appear on every (1–4)n bases along a random DNA chain. The equation states how many fragments ends (measured in moles) are produced when a restriction enzyme cuts DNA.
Moles of DNA ends =2x(grams of DNA)/(number of bp)(660 g/mol / bp).
The equation describes how many ends are produced when circular DNA is digested by a restriction enzyme.
Mole ends=2x(moles DNA)x number of restriction sites.
The following equation can be used to determine how many ends are produced during the digestion of a linear molecule by a restriction endonuclease.
Mole ends=2x(molesDNA)number of restriction sites +[2x(moles of DNA)].
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Answer:
a pet parrot talking
Explanation:
dogs responding to "roll over"
Answer:
% of wolves have normal fur.
Explanation:
Given , the allele for white fur is recessive and the allele for normal fur is dominant
Let "N" represents the allele for normal fur and "n" represents the fur for white fur.
As per Hardy Weinberg's principle, the frequency for dominant allele is represented by "p"
Given ,
Then frequency for dominant genotype will be "
"
So, Frequency for wolves with normal fur is

Percentage of the wolves with normal fur is
%