Answer:
See below for answer
Explanation:
<u>A. 200 mOsM NaCl</u>
This solution is hypotonic to the red blood cell (RBC) with penetrating solute. The RBCs will swell up and burst because the water will move into the cells.
<u>B. 400 mOsM urea</u>
This solution is hypertonic to the RBCs with non-penetrating solutes. Water will leave the cells via osmosis and the cells will shrink and appear shriveled.
<u>C. 100 mOsM urea plus 200 mOsM NaCl</u>
This time both penetrating and non-penetrating solute is present. The solution is isotonic to the RBCs and although there will be movement of water between the cells and the solution, there will be no overall change in the concentration of water for each and no change in appearance of the cells.
<u>D. 300 mOsM urea</u>
The RBCs will not lyse nor shrivel as again the solution is isotonic to the RBCs.
Answer:
Explanation:
Hello friend,
<u><em>The answer is b) Removal of anthers</em></u>
Hope this helps
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B. Subgroups
<span>When constructing a dichotomous key, the first step is to look at the group of objects or organisms and separate them into two groups based on a single distinguishing characteristic. Then continue to separate each of the groups until each object has its own separate set of characteristics.</span>
Absorption is the correct answer
Answer:
I'm pretty sure it B, hope I helped
