3 years ago

0.04b + 13 ≥ 0.46 - 8.6I forgot how to do this help

Mathematics

1 answer:

krek1111 [17]3 years ago

8 0

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A factory received a shipment of 11 hammers, and the vendor who sold the items knows there are 2 hammers in the shipment that ar

zhenek [66]

Question:

If a sample of 2 hammer is selected

(a) find the probability that all in the sample are defective.

(b) find the probability that none in the sample are defective.

Answer:

a $Pr = \frac{2}{110}$

b $Pr = \frac{72}{110}$

Step-by-step explanation:

Given

$n = 11$ --- hammers

$r = 2$ --- selection

This will be treated as selection without replacement. So, 1 will be subtracted from subsequent probabilities

Solving (a): Probability that both selection are defective.

For two selections, the probability that all are defective is:

$Pr = P(D) * P(D)$

$Pr = \frac{2}{11} * \frac{2-1}{11-1}$

$Pr = \frac{2}{11} * \frac{1}{10}$

$Pr = \frac{2}{110}$

Solving (b): Probability that none are defective.

The probability that a selection is not defective is:

$P(D') = \frac{9}{11}$

For two selections, the probability that all are not defective is:

$Pr = P(D') * P(D')$

$Pr = \frac{9}{11} * \frac{9-1}{11-1}$

$Pr = \frac{9}{11} * \frac{8}{10}$

$Pr = \frac{72}{110}$

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3 years ago

12 inches to millimeters

gogolik [260]

The answer is 304.8 millimetres

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3 years ago

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Which statements about the histogram are true? Check all that apply.

Ipatiy [6.2K]

Answer:

the other person is wrong, its b, d, e, and f

Step-by-step explanation:

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4 years ago

There are 300 students. for every 8 are boys, and for every seven are girls. how many boys?

katen-ka-za [31]

8+7=15
300/15=20
8 x 20 =160 Boys
7 x 20 = 140 girls

140 + 160 = 300

Hope this helps!

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3 years ago

Which of the following represents this function written in intercept form?

rodikova [14]

The answer is

C. - (x + 3)(x - 4)

because if you solve this....

- (x + 3)(x - 4)
(-x - 3)(x - 4)
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-x^2 + x + 12

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3 years ago

0.04b + 13 ≥ 0.46 - 8.6I forgot how to do this help​

0.04b + 13 ≥ 0.46 - 8.6I forgot how to do this help