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kvv77 [185]
3 years ago
7

I am a 3 digit number that has a 2 in the hundreds place. I am divisible by 3,4, and 5. What number am I?

Mathematics
1 answer:
Nastasia [14]3 years ago
4 0
4x60=240
3x80=240
5x48=240
Answer 240
Hope that helps!


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Jessica and Maria got to the supermarket to buy fruit. Jessica
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$0.30 per orange

Step-by-step explanation:

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2/5m - 4/5 - 3/5m please skrelp
netineya [11]
2/5m - 4/5 - 3/5m...combine like terms
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A large university accepts 60​% of the students who apply. Of the students the university​ accepts, 40​% actually enroll. If 30,
kykrilka [37]

Answer:

7,200

Step-by-step explanation:

Let's start by calculating how many students the university accepts. The problem says they accept 60% of the students. 60% as a decimal is 0.6. To calculate 60% of something, you multiply .60 by whatever quantity. In this case, it would be the students.

Number of accepted students = .6 * 30000 = 18,000

The university accepts 18,000 students.

Now, the next problem is that of those accepted students, we need to find out how many actually enroll. The problem says they accept 40% of the accepted students. Applying the same principle,

Number of enrolled students = .4 * 18000 = 7,200

The number of students that actually enroll is 7,200.

Alternatively, .6 * 30000 * .4 would give you the same result.

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3 0
2 years ago
What is 735,249-575,388 equal?
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8 0
3 years ago
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HELP!!<br>Find the third term of (x^2+3y)^3
lana66690 [7]

Answer:

T_{3}=27{x}^{2}y^2

Step-by-step explanation:

The given binomial expression is:

( {x}^{2} + 3y)^{3}

When we compare to:

{(a +b)}^{n}

We have

a =  {x}^{2}

b = 3y \\ n = 3

The nth term is given by;

T_{r+1}=^nC_ra^{n-r}b^r

To find the 3rd term, we put:

r + 1 = 3 \\ r = 2

We substitute into the formula to get:

T_{3}=^3C_2( {x}^{2} )^{3-2}(3y)^2

We simply:

T_{3}=3( {x}^{2} )^{1} \times 9y^2

T_{3}=27{x}^{2}y^2

3 0
3 years ago
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