2 + 3(x + 2x) = −2x(2 − 4) + 1 A) −5 B) − 1 5 C) 5 D) 1 5

Mathematics

1 answer:

11Alexandr11 [23.1K]3 years ago

4 0

Answer:

B -1/5

you have to follow pemdas first get rid of the parethase which leaves you with 2+3x+6x=-4x+8x+1 then you add what you can do then you get 2+9x=4x+1 then you subtract 2 from both sides and subtract 4x from both sides which leaves you with 5x=-1 then you divide 5 from both sides and get x=-1/5

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The table below shows the total cost (TC) and marginal cost (MC) for Choco Lovers, a monopolistic firm producing different quant

goblinko [34]

Answer:

Spreadsheet values

B3 = $15 (shown)
C4 = $420 (shown)
D6 = $272.5
E4 = $6
F2 = $16
F6 = $5

Other values

profit maximizing Q: 35
profit maximizing P: $13
maximum profit: $227.5

Step-by-step explanation:

Labeling the columns of the spreadsheet A--F, and the rows 1--7, we want to find the values as follows.

a) The relationship between quantity, price, and revenue is ...

total revenue = quantity × price

price = (total revenue)/quantity

Then ...

B3 = 375/25 = 15 (as shown)
C4 = 30×14 = 420 (as shown)

b) The relationship between total cost and marginal cost is ...

mc2 = (tc2 -tc1)/(q2 -q1)

tc2 = (mc2)(q2 -q1) +tc1

Then ...

D6 = 9(40 -35) +227.5 = 272.5
E4 = (192.5 -162.5)/(30 -25) = 6

c) Marginal revenue is figured the same way as marginal cost.

mr2 = (r2 -r1)/(q2 -q1)

Then ...

F2 = (320 -0)/(20 -0) = 16
F6 = (480 -455)/(40 -35) = 5

d) The quantity maximizing profit will be the quantity such that marginal revenue is equal to marginal cost. That is, marginal profit is zero. That quantity is 35, where both marginal cost and marginal revenue are 7.

e) The price at a quantity of 35 is 13. This value is read from the given table.

f) The maximum profit is the difference between revenue and cost at the profit-maximizing quantity:

maximum profit = 455 -227.5 = 227.5

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3 years ago

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% exponential notation 2nd form
{{ a}}^y={{ b}}\implies log_{{ a}}{{ b}}=y\\\\
-------------------------------\\\\
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now, look closely, what "k" value, what exponent, negative or fraction or positive, will ever make "e" to 0? none, so one can say is "undefined".

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aleksklad [387]

Answer:

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set up a proportion of 226800/100 and 19300/x.

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