Let h = height of the box,
x = side length of the base.
Volume of the box is

.
So

Surface area of a box is S = 2(Width • Length + Length • Height + Height • Width).
So surface area of the box is


The surface are is supposed to be the minimum. So we'll need to find the first derivative of the surface area function and set it to zero.

![4x = \frac{460}{ x^{2} } \\ 4x^{3} = 460 \\ x^{3} = 115 \\ x = \sqrt[3]{115} = 4.86](https://tex.z-dn.net/?f=%204x%20%3D%20%5Cfrac%7B460%7D%7B%20x%5E%7B2%7D%20%7D%20%20%5C%5C%20%204x%5E%7B3%7D%20%3D%20460%20%20%5C%5C%20x%5E%7B3%7D%20%3D%20115%20%20%5C%5C%20x%20%3D%20%20%5Csqrt%5B3%5D%7B115%7D%20%3D%204.86%20)
Then

So the box is 4.86 in. wide and 4.87 in. high.
Answer:
x < 2
Step-by-step explanation:
5(2x + 8) < 60 ( divide both sides by 5 )
2x + 8 < 12 ( subtract 8 from both sides )
2x < 4 ( divide both sides by 2 )
x < 2
Answer:
Option a) Type I error would occur if we reject null hypothesis and conclude that the average amount is greater than $3,200 when in fact the average amount is $3,200 or less.
Step-by-step explanation:
We are given the following information in the question:

where μ is the average amount of money in a savings account for a person aged 30 to 40.
Type I error:
- Type I error is also known as a “false positive” and is the error of rejecting a null hypothesis when it is actually true.
- In other words, this is the error of accepting an alternative hypothesis when the results can be attributed by null hypothesis.
- A type I error occurs during the hypothesis testing process when a null hypothesis is rejected, even though it is correct and should not be rejected.
Thus, in the above hypothesis type error will occur when we reject the null hypothesis even when it is true.
Option a) Type I error would occur if we reject null hypothesis and conclude that the average amount is greater than $3,200 when in fact the average amount is $3,200 or less.
The answer is
2x+(3x+4)=6
Answer:
9x + 1 = 7x + 13
<=> 2x = 12
<=> x = 6
with x = 6, UW = 7.6 + 13 = 55
Step-by-step explanation:
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