Answer:
3 hours for miss patrick 5 hours for mr shah
Step-by-step explanation:
Answer:
Step-by-step explanation:
Here is my answer. Let just give assumptions. For example,the relationship is linear.Therefore the slope, "m," is the same throughout.
Let us make patrons the independent variable, the two points are: (1314, 11333) and (1544, 13518).
m = (13518-11333)/(1544-1314)
m = 9.5
profit = 9.5 patrons (you pick the variable names)
For 1 more patron substitute 1:
profit = 9.5 (1)
profit = 9.5
Isolate "patrons" and you get the function based on profit:
patrons = profit/9.5
The break even point is for 0 < profit.
0 < profit = 9.5 patrons
0 < 9.5 patrons
0 < patron
All the numbers in this range can be written as

with

and

. Construct a table like so (see attached; apparently the environment for constructing tables isn't supported on this site...)
so that each entry in the table corresponds to the sum of the tens digit (row) and the ones digit (column). Now, you want to find the numbers whose digits add to perfect squares, which occurs when the sum of the digits is either of 1, 4, 9, or 16. You'll notice that this happens along some diagonals.
For each number that occupies an entire diagonal in the table, it's easy to see that that number

shows up

times in the table, so there is one instance of 1, four of 4, and nine of 9. Meanwhile, 16 shows up only twice due to the constraints of the table.
So there are 16 instances of two digit numbers between 10 and 92 whose digits add to perfect squares.
Answer:
My student the slope paserea the Pointe 6w and 10,4 is8