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3 years ago

Which of the following point-slope form equations could be produced with the points (-5, -2) and (1, 2)?

Mathematics

1 answer:

Kitty [74]3 years ago

5 0

Answer:

Step-by-step explanation:

when putting points into the equation, you change the signs. slope doesn't change its sign.

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Triangle ABC was dilated using the rule Do.4. Triangle

pshichka [43]

Answer:

The correct option is B. The length of OB' is 3 units.

Step-by-step explanation:

The rule of dilation is D₀,₄. It means dilation by scale factor 4 with center of dilation is origin.

$\text{Scale factor}=\frac{\text{Distance between center and any point of the image}}{\text{Distance between center and corresponding point of the Preimage}}$

$\text{Scale factor}=\frac{OB'}{OB}$

$4=\frac{OB'}{\frac{3}{4}}$

$4\times \frac{3}{4}=OB'$

$3=OB'$

The length of OB' is 3 units. Therefore the correct option is option is B.

6 0

4 years ago

Read 2 more answers

How to find mean and standard deviation for binomial distribution?

denis-greek [22]

Thanks for the points oh and idk

6 0

3 years ago

Solve the equation, keeping the value for x as an improper fraction.

vekshin1

Answer:

30/7

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

The area of a parallelogram i 12 quare unit. One ide of the parallelogram i 18 unit long. The other ide i 6 unit long. Determine

mars1129 [50]

The possible heights of the parallelogram are 2/3 and 3

So, the correct option is A and C

The given expression:

area of a parallelogram, A = 12 square unit

a side of the parallelogram, = 18 units

another side of the parallelogram = 6 units

let,

the height of the parallelogram, h

The area of a parallelogram is given as;

Area = base (b) x height (h)

height (h) = Area/base(b)

From the given sides, the possible heights of the parallelogram are calculated as follows;

if the base, b = 18 units

height(h) = 12/18

= 2/3

Also, if the base, b = 6 units

height(h) = 12/6

= 2

Therefore, the possible heights of the parallelogram are 2/3 and 2

Learn more here: brainly.com/question/24054192

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8 0

1 year ago

Linear equations. write the standard form of an equation of the

erastova [34]

Answer:

The standard form of an equation of the line that passes through the given point having slope is $y-y_{1} =m(x-x_{1}$

Step-by-step explanation:

The standard form of an equation of the line that passes through the given point ( $(x_{1} ,y_{1} )$ and having slope m is

$y-y_{1} =m(x-x_{1}$

another form of an equation of the line that passes through the given point ( $(x_{0} ,y_{0} )$ and having slope m is

$y-0 =m(x-0)$

y=m x

7 0

4 years ago