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Marat540 [252]
2 years ago
11

Graham's sunflower is 2 feet tall. Katie's sunflower is 1 foot 8 inches tall. How many inches taller is Graham's sunflower than

Katie's sunflower? Show Work!
(A) 4 inches
(B) 6 inches
(C) 16 inches
(D) 20 inches

Leanne jumped a distance of 3 feet 8 inches. Monica jumped a distance of 4 feet 6 inches. How many more inches did Monica jump than Leanne? { 1 foot = 12 inches}
(A) 8 inches
(B) 10 inches
(C) 12 inches
(D) 14 inches
Mathematics
1 answer:
timofeeve [1]2 years ago
8 0

Answer:

question one : 4  question two : 8

Step-by-step explanation

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Carlos drew a plan for his garden on a coordinate plane. Rose bushes are located at A(–5, 4), B(3, 4), and C(3, –5)
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Given:

A(-5,4)

B(3,4)

C(3,-5)

So point D is:

so point D is (-5,-5)

For AB is

Distance between two point is:

\begin{gathered} (x_1,y_1)and(x_2,y_2) \\ D=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2} \end{gathered}

so distance between A(-5,4) and B(3,4) is:

\begin{gathered} D=\sqrt[]{(3-(-5))^2+(4-4)^2} \\ =\sqrt[]{(8)^2+0^2} \\ =8 \end{gathered}

So AB is 8 unit apart.

For B(3,4) and C(3,-5).

\begin{gathered} D=\sqrt[]{(3-3)^2+(-5-4)^2} \\ =\sqrt[]{0^2+(-9)^2} \\ =9 \end{gathered}

So BC is 9 unit apart.

For fourth bush point is (-5,-5) it left of point C(3,-5) is:

\begin{gathered} D=\sqrt[]{(3-(-5))^2+(-5-(-5))^2} \\ =\sqrt[]{(8)^2+0^2} \\ =8 \end{gathered}

so fourth bush is 8 unit left of C.

For fourth bush(-5,-5) below to point A(-5,4)

\begin{gathered} D=\sqrt[]{(-5-(-5))^2+(4-(-5))^2} \\ =\sqrt[]{0^2+9^2} \\ =9 \end{gathered}

so fourth bush 9 units below of A.

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