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Sergio039 [100]
3 years ago
15

In the following shape, two semicircles have been placed at the end of a rectangle whose length is twice its height. Which of th

e following gives the length around this figure in terms of the semicircle's radius, r?
Mathematics
1 answer:
mixas84 [53]3 years ago
4 0

Answer:

Perimeter of the figure is 2r(\pi + 6)

Step-by-step explanation:

Perimeter of a shape is total length of the boundaries of the shape. In the given question, we have two semicircles and a rectangle.

The circumference of a circle = 2\pir, thus the length of the arc of a semicircle = \pir.

The height of the rectangle is h, radius 'r' of the semicircle = \frac{h}{2}

⇒                             h = 2r

The perimeter of a rectangle = 2(l +b).

Given that: the length is twice its height, so that:

length = 2h

Perimeter of the rectangle = 2 (2h + h)

                                            = 6h

But,        h = 2r

Perimeter of the rectangle = 6 × 2r  

                                            = 12r      

Perimeter of the figure in terms of the semicircle's radius = \pir + 12r  + \pir

                                                                                               = 2\pir + 12r

                                                                                   = 2r(\pi + 6)

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Step-by-step explanation:

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The expression for the number of segments drawn out of the n number of points in the circle is,
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A coin is weighted so that the probability of obtaining a head in a single toss is 0.3. If the coin is tossed 35 times, what is
Vlada [557]

Answer:

(1) The correct answer is option (a) 0.510

(2) The correct answer is option (b) = 0.9664

(3) The correct answer is option (a)  0.8665

Step-by-step explanation:

1. Find attached of question 1

2.

n= 850

p= 0.1400  

here mean of distribution(μ) =n*p

                                               =850* 0.1400

                                                = 119  

standard deviation σ = √(np(1-p))

                                    = √(850*0.1400(1-0.1400))

                                    = √102.34

                                       =10.1163  

for normal distribution z score =(X-μ)/σx    

therefore from normal approximation of binomial distribution and continuity correction:

probability = P(X>100.5)

                   = P(Z>-1.83)

                   = 1-P(Z<-1.83)

                   = 1-0.0336

                   = 0.9664

3.

n = 1000

p = 0.08

mean of distribution(μ) =np

                                       = 1000*0.08

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and standard deviation σ=√(np(1-p))

                                    = √(1000*0.08(1-0.08))

                                    = √736

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                    = 1-P(Z<-1.11)

                    = 1-0.1335

                    = 0.8665

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