The answer is C. That is where the graph crosses the x axis
You forgot to say what the question actually is !
But I've seen this problem before, in the last few days, here on Brainly.
I think the problem has three parts: 1). Solve the equation for 'a';
2). Solve it for 'b'; and 3). Solve it for 'c'.
I'll slog through that, and I'll try to explain what I'm doing clearly enough
so that eventually, you can do it on your own ... which is really the whole
idea behind this website.
1). Solve the equation for 'a'. That means you have to wind up with something
that says a = everything else.
<u>D = (a + b + c) / c</u>
Split the right side into 3 fractions: D = a/c + b/c + c/c
But c/c =1 , so the equation says D = a/c + b/c + 1
Subtract (b/c +1) from each side: D - b/c - 1 = a/c
Multiply each side by 'c' : <em>Dc - b - c = a</em>
========================
2). Solve the equation for 'b'. That means you have to wind up with something
that says b = everything else.
<u>D = (a + b + c) / c</u>
Split the right side into 3 fractions: D = a/c + b/c + c/c
But c/c =1 , so the equation says D = a/c + b/c + 1
Subtract (a/c +1) from each side: D - a/c - 1 = b/c
Multiply each side by 'c' : <em>Dc - a - c = b</em>
==========================
3). Solve the equation for 'c'. That means you have to wind up with
something that says c = everything else.
<u>D = (a + b + c) / c</u>
Split the right side into 3 fractions: D = a/c + b/c + c/c
But c/c =1 , so the equation says D = a/c + b/c + 1
Subtract 1 from each side: D - 1 = a/c + b/c
The two fractions on the right can be added/combined: D - 1 = (a + b) / c
Multiply each side by 'c' : c(D - 1) = (a + b)
Divide each side by (D - 1) : <em>c = (a + b) / (D - 1)</em>
Answer:
= x
Step-by-step explanation:
Basically, find the missing side lengths of each triangle so that you can solve for x:
1. right triangle w/ side lengths 48 and 52
- 48^2 + (missing side)^2 = 52^2
- 2304 + (missing side)^2 = 2704
- (missing side)^2 = 400
- (missing side) = 20 (use this for next triangle)
2. right triangle w/ side lengths 12 and 20 (from previous triangle)
- 12^2 + (missing side)^2 = 20^2
- 144 + (missing side)^2 = 400
- (missing side)^2 = 256
- (missing side) = 16 (will be used with next triangle's missing side)
3. right triangle w/ side lengths 5 and 13
- 5^2 + (missing side)^2 = 13^2
- 25 + (missing side)^2 = 169
- (missing side)^2 =144
- (missing side) = 12
Take right triangle w/ side lengths 12, 20, and 16 (#2) and right triangle w/ side lengths 5, 13, and 12 (#3):
- the value of 12 (missing side of #3) subtracted from the #2's missing side, 16, (not its hypotenuse that equals 20 which was found from #1) will equal <u>the missing side length that will be used to find 'x'</u>
- 16 - 12 = 4 ---> so the side lengths are 4, 5, and x
4. Solve for the final triangle that includes x:
- 4^2 + 5^2 = x^2
- 16 + 25 = x^2
- 41 = x^2
- = x
The awnser is C,............