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Reptile [31]
3 years ago
5

D=a+b+c over ac. If you under stand please help

Mathematics
2 answers:
White raven [17]3 years ago
8 0
You forgot to say what the question actually is ! 

But  I've seen this problem before, in the last few days, here on Brainly. 
I think the problem has three parts:  1). Solve the equation for 'a'; 
2). Solve it for 'b'; and 3). Solve it for 'c'.

I'll slog through that, and I'll try to explain what I'm doing clearly enough
so that eventually, you can do it on your own ... which is really the whole
idea behind this website.

1).  Solve the equation for 'a'.  That means you have to wind up with something
that says      a = everything else.

<u>D = (a + b + c) / c</u>

Split the right side into 3 fractions:      D = a/c + b/c + c/c

But  c/c =1 ,  so the equation says      D = a/c + b/c + 1

Subtract  (b/c +1)  from each side:      D - b/c - 1  =  a/c

Multiply each side by 'c' :                  <em>Dc - b - c  =  a</em>
========================

2).  Solve the equation for 'b'.  That means you have to wind up with something
that says      b = everything else.

<u>D = (a + b + c) / c</u>

Split the right side into 3 fractions:      D = a/c + b/c + c/c

But  c/c =1 ,  so the equation says      D = a/c + b/c + 1

Subtract  (a/c +1)  from each side:      D - a/c - 1  =  b/c

Multiply each side by 'c' :                  <em>Dc - a - c  =  b</em>
==========================

3).  Solve the equation for 'c'.  That means you have to wind up with
something that says      c = everything else.

<u>D = (a + b + c) / c</u>

Split the right side into 3 fractions:      D = a/c + b/c + c/c

But  c/c =1 ,  so the equation says      D = a/c + b/c + 1

Subtract  1  from each side:          D - 1 = a/c + b/c

The two fractions on the right can be added/combined:    D - 1 = (a + b) / c

Multiply each side by  'c' :          c(D - 1) = (a + b)

Divide each side by  (D - 1) :      <em>c  =  (a + b) / (D - 1)</em> 
Anarel [89]3 years ago
6 0
Plug in the numbers

For example
A-2
B-3
C-8

Your problem would be 2+3+8 divided by 2 times 8
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Read 2 more answers
Why is the answer A? Plzzz explain.
Contact [7]

Answer:


Step-by-step explanation:

f(x) = x^2 + 4x + 4

f(x + a) = (x + a)^2 + 4(x + a) + 4

f(x + a) = x^2 + 2ax + a^2 + 4x + 4a + 4   Now combine like terms and use the distributive property.

f(x + a) = x^2 + (2a + 4)x + a^2 + 4a + 4

We are told that f(x + a) = x^2 - 6x + 9

So that means that

2a + 4 = - 6      Subtract 4 from both sides.

2a = - 6 - 4

2a = - 10          Divide by 2

a = - 10/2

a = - 5.            

But you are not finished. You have to check the last part.

a^2 + 4x + 4 = 9

(a + 2)^2 = 9

Take the square root of both sides

sqrt(a+ 2)^2 = +/- 3

a+2 = 3

a = 1.

Does this work or is it extraneous? It is extraneous because it will not work for  2(a) + 4 = - 6  

You get 6 = - 6 which is not correct. But you did give the second best answer.

a + 2 = - 3

a = - 3 - 2

a = - 5 which agrees with your previous answer.

===========

This is an extremely hard or tricky or sneaky problem. It takes a lot of conniving to get the right answer and 1 is not a left field answer. It just does not happen to be correct.

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