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iragen [17]
4 years ago
10

4 examples of soft rocks​

Physics
2 answers:
Arlecino [84]4 years ago
5 0

Answer:

Limestone, flagstone, sandstone, and igneous rock.

DIA [1.3K]4 years ago
5 0
Mudstone, chalk, coal, shale
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What is heredity? i think its physics
Rashid [163]
It's the passing of traits/characteristics from the parent(s) to the offspring(kids).<span>This is how offspring cells become predisposed to the genes/traits of the parent cells</span>.
8 0
3 years ago
Work out the current through an electric kettle with a power of 2.2 kW if it uses the 180 V mains supply. Round your answer to 2
weeeeeb [17]

Answer:

12 A

Explanation:

Given,

Power of electric kettle=2.2 kW=2200W (since 1kW=1000W)

Voltage=180V

Current=?

Power = Voltage*Current

Current = Power ÷ Voltage

=2200W ÷ 180V

=12.22 Ampere

=12 A

7 0
3 years ago
Betelgeuse is 100,000 times more luminous than our sun, which means that it releases an estimated 3.846 x 1031 W of luminous lig
denis-greek [22]

Answer:

5.4  × 10⁸ W/m²

Explanation:

Given that:

The Power (P) of Betelgeuse is estimated to release 3.846 × 10³¹ W

the mass of the exoplanet = 5.972 × 10²⁴ kg

radius of the earth = 1.27 × 10⁷ m

half the distance (i.e radius r ) = 7.5  × 10¹⁰ m

a) What is the intensity of Betelgeuse at the "earth’s" surface?

The Intensity of  Betelgeuse  can be determined by using the formula:

Intensity \ I = \frac{P}{4 \pi r^2}

I = \frac{3.846*10^{31}}{4 \pi (7.5*10^{10})^2}

I = 544097698.8 W/m²

I = 5.4  × 10⁸ W/m²

8 0
3 years ago
Read 2 more answers
To meet a U.S. Postal Service requirement, employees' footwear must have a coefficient of static friction of 0.5 or more on a sp
Vlada [557]

Answer:

the minimum time interval is 0.77 seconds

Explanation:

given data

coefficient of static friction = 0.5

coefficient of static friction shoes= 0.825

travel s = 2.40 m

to find out

what is the minimum time interval

solution

we know newton 2nd law

force = mass × acceleration

and

force acting on person due to friction

force = coefficient of static friction shoes × mg

so we can say

coefficient of static friction shoes × mg = ma

so

a = coefficient of static friction shoes × g

and we know g is 9.8 m/s²

so

distance formula by kinematic relation

distance = ut + 0.5 × at²

here put a value and u is zero because initial speed

2.40 = 0 + 0.5  × coefficient of static friction shoes × g× t²

2.40 = 0.5  × 0.825 × 9.8 × t²

t = 0.77 s

the minimum time interval is 0.77 seconds

5 0
4 years ago
A body goes from P to Q with a velocity of 10 m/s and comes back from Q to P with a velocity of 20 m/s. What is the average velo
Pachacha [2.7K]
Let's say the distance is D. Then the time going is D/10 sec. The time returning is D/20 s. The total time is 3D/20 s, and the total distance is 2D. The average speed for the round trip is (total distance)/(total time). That's (2D) ÷ (3D/20). That's (40D/3D) which is 13-1/3 m/s. (I thought it was going to depend on the distance, but it doesn't.)
5 0
3 years ago
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