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11Alexandr11 [23.1K]
3 years ago
11

A tutor kept track of how many students she had helped every week for a year. The range of the number of tutored

Mathematics
1 answer:
zzz [600]3 years ago
3 0

Answer: the same time as the first time in the future and the other is a great way to get the best out of the way and I have to say that this was not.

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(y-5)6+15–5y=5<br> What does the variable represent?
Strike441 [17]

Answer:

2.75

Step-by-step explanation:

(y-5)6+15–5y=5

(y-5+5)6-6+15-15–5y=5-6-15+5

y-5y=-11

-4y/-4=-11/-4

y=2.75

8 0
4 years ago
I need the missing blanks .
MrRissso [65]

Answer:

K, (-3.5,-5), E, (3.5, 3)

Step-by-step explanation:

8 0
3 years ago
What is 69 x 420 <br> Can you sub to me please?
Alex17521 [72]

Answer:

69x420=28,980

Step-by-step explanation:

i will

6 0
3 years ago
Read 2 more answers
6a - 5b when a = -3 and b = 4
DIA [1.3K]

Given.

6a - 5b

Plug in values.

6(-3) - 5(4) =

-18 - 20 =

-38

8 0
3 years ago
Read 2 more answers
How does this polynomial identity work on numerical relationships?<br> (y + x) (ax + b)
Serggg [28]

Let us take 'a' in the place of 'y' so the equation becomes

(y+x) (ax+b)

Step-by-step explanation:

<u>Step 1:</u>

(a + x) (ax + b)

<u>Step 2: Proof</u>

Checking polynomial identity.

(ax+b )(x+a) = FOIL

(ax+b)(x+a)

ax^2+a^2x is the First Term in the FOIL

ax^2 + a^2x + bx + ab

(ax+b)(x+a)+bx+ab is the Second Term in the FOIL

Add both expressions together from First and Second Term  

= ax^2 + a^2x + bx + ab

<u>Step 3: Proof </u>

(ax+b)(x+a) = ax^2 + a^2x + bx + ab

Identity is Found .

Trying with numbers now

(ax+b)(x+a) = ax^2 + a^2x + bx + ab

((2*5)+8)(5+2) =(2*5^2)+(2^2*5)+(8*5)+(2*8)

((10)+8)(7) =(2*25)+(4*5)+(40)+(16)

(18)(7) =(50)+(20)+(56)

126 =126

3 0
4 years ago
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