180 IF LCM OF 12 AND A NUMBER, M. WHAT ARE POSSIBLE VALUE OF M?

Find the area of the shaded regions. Give your answer as a completely simplified exact value in terms of pi (no approximations)

Kisachek [45]

Answer:

40π in^2

Step-by-step explanation:

360°/72°=5

so, each of the two shaded regions are 1/5 of the circle.

the formula for finding the area of a circle is πr^2, so:

area for one of the shaded regions:

1/5πr^2

1/5π(10)^2

1/5π100

20π in^2

this means that the area for one of the shaded regions is 20π. however, since there are two of them:

2(20π)=40π

so, the area of the shaded regions is 40πin^2

5 0

3 years ago

How can this be solved?

Ad libitum [116K]

Answer:

by multiplying all numbers seperatly by each other and adding those

Step-by-step explanation:

7 0

3 years ago

(25 points, please help! Brainliest!) Mrs. Hanger is painting the following picture of an H to hang in the entryway of her home.

disa [49]

Answer:

the new scale is the same length as the original scale

7 0

3 years ago

Which one equals 16 if you set it up like this? Please Halp

Sveta_85 [38]

The first one equals 16. The second one equals 0.0625

6 0

3 years ago

At Western University the historical mean of scholarship examination scores for freshman applications is 900. A historical popul

vampirchik [111]

Answer:

a) Null Hypothesis: $\mu =900$

Alternative hypothesis: $\mu \neq 900$

b) The 95% confidence interval would be given by (910.05;959.95)

c) Since we confidence interval not ocntains the value of 900 we fail to reject the null hypothesis that the true mean is 900.

d) $z=\frac{935 -900}{\frac{180}{\sqrt{200}}}=2.750$

Since is a bilateral test the p value is given by:

$p_v =2*P(Z>2.750)=0.0059$

Step-by-step explanation:

a. State the hypotheses.

On this case we want to check the following system of hypothesis:

Null Hypothesis: $\mu =900$

Alternative hypothesis: $\mu \neq 900$

b. What is the 95% confidence interval estimate of the population mean examination score if a sample of 200 applications provided a sample mean x¯¯¯= 935?

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=935$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

$\sigma=180$ represent the population standard deviation

n=200 represent the sample size

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

In order to calculate the mean and the sample deviation we can use the following formulas:

$\bar X= \sum_{i=1}^n \frac{x_i}{n}$ (2)

$s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}}$ (3)

The mean calculated for this case is $\bar X=3278.222$

The sample deviation calculated $s=97.054$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that $z_{\alpha/2}=1.96$