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grin007 [14]
3 years ago
9

Suppose I am playing a sport that does not allow me to end a match in a tie​ (AKA I have to either win or​ lose). If my probabil

ity of winning at any given time is​ 0.6, find the probability that I win exactly three of five matches
Mathematics
1 answer:
Leviafan [203]3 years ago
6 0

Answer: The required probability is 0.3456.

Step-by-step explanation:

Since we have given that

Probability of winning at any given time = 0.6

Probability of losing at any given time = 1-0.6 = 0.4

Number of total matches = 5

Number of won matches = 3

So, using "Binomial distribution", we get that

P(X=3)=^5C_3(0.6)^3(0.4)^2\\\\P(X=3)=0.3456

Hence, the required probability is 0.3456.

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the variable Z is invery proportional to X. when X is 3, Z has the value 6. what is the value of Z when X = 12
MrMuchimi

"inversely proportional," please.

z = k/x

When x is 3, z = 6; find k: 6 = k/3, or k = 18.

Then z = 18/x. When x = 12, z = 18/12 = 2/3 (answer)

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kakasveta [241]
For this case we have the following function:
 f (x) = (1/3) * (4 ^ x)
 We must evaluate the function for x = 2
 We have then:
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 Rewriting:
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option A
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