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9966 [12]
3 years ago
10

You own a motel and have a pricing structure that encourages rentals of rooms in groups.

Mathematics
1 answer:
zheka24 [161]3 years ago
5 0

Answer:

$41

Step-by-step explanation:

  • One room rents for $68,
  • Two rooms for $65 each,
  • In general, the group rate per room is found by taking $3 off the base of $68 for each extra room.

So,

a_1=\$68\\ \\a_2=\$65\\ \\a_3=\$62\\ \\...

where a_n is the rate per nth room rented.

This is an arithmetic sequence, so

a_n=a_1+(n-1)\cdot d

In your case,

a_1=68\\ \\n=10\\ \\d=-3

Hence

a_{10}=68+(10-1)\cdot (-3)=68-9\cdot 3=68-27=41

This means if a group rents 10 rooms, the charge per room is $41.

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N = first integer 
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n + 3 = fourth 

the sum is 114 so: 

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so your first four integers are: 27 28 29 and 30 


(I'll also help with one) 

week one: x 
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so its: 

x + (x+5) + (2x + 10) 
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its then: 

week one: 104 sold 
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</span>
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