A bag contains 7 purple beads,4 blue beads,and 4 pink beads.What is the probability of not drawing a pink bead?

2 answers:

7 0

There are 11 possibilities that are what you want, and 4 that you don't want. So, the probability of drawing a bead that is not pink is:

$\frac{11}{11+4} = \frac{11}{15} \approx 73\%$

otez555 [7]4 years ago

4 0

I want the phone so your answer is simple

7+4+4= 15

15-4=11

you answer is 11:4

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Write the measure -128 30' 45" as a decimal to the nearest thousandth

miv72 [106K]

Minutes are equal to 1/60ths and seconds are equal to 1/3600ths so

-128+30/60+45/3600

-128.5125

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3 years ago

Parts being manufactured at a plant are supposed to weigh 65 grams. Suppose the distribution of weights has a Normal distributio

andrew-mc [135]

Answer:

0.64%.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .