All categories

4 years ago

I need help solving this:y+8x=4

Mathematics

2 answers:

slamgirl [31]4 years ago

6 0

Well there could be many possible outcomes for example it could be 2+8x0.25 while following pemdass

olga2289 [7]4 years ago

4 0

Y=0.5 because you need to divide 8 from 8x and 4. So the answer is y=0.5... I hope that helps.

You might be interested in

Guys I need help on all three please

kodGreya [7K]

Answer:

graph 1 proportional

graph 2&3 is non proportional

i think

6 0

3 years ago

The soccer team and the lacrosse team sold tubs of cookie dough as a fundraiser. Each tub sold earns $5 in profit. If the soccer

Anna [14]

I think it would be 99 i hope this help you

6 0

3 years ago

Read 2 more answers

Read the instructions

nordsb [41]

Answer:

Step-by-step explanation:

$\frac{5x - 2}{4}+\frac{1}{2}=\frac{3y+2}{2}$

Multiply the equation by 4

$4*\frac{5x - 2}{4}+4*\frac{1}{2}=4*\frac{3y+2}{2}\\$

5x - 2 + 2 = 2*(3y + 2)

5x +0 = 2*3y + 2*2

5x = 6y + 4

5x - 6y = 4 --------------------(I)

$\frac{7y+3}{3}=\frac{x}{2}+\frac{7}{3}\\$

Multiply the equation by 6

$6*\frac{7y+3}{3}=6*\frac{x}{2}+6*\frac{7}{3}\\$

2*(7y + 3) = 3x + 2*7

14y + 6 = 3x + 14

14y = 3x + 14 - 6

14y = 3x + 8

-3x + 14y = 8 ------------------------(II)

Multiply equation (I) by 3 and equation (II) by 5 and then add

(I)*3 15x - 18y = 12

(II)*5 <u>-15x + 70y = 40</u> {Now add}

52y = 52

y = 52/52

y = 1

Substitute y =1 in equation (I)

5x - 6*1 = 4

5x - 6 = 4

5x = 4 +6

5x = 10

x = 10/5

x = 2

7 0

3 years ago

Jenny surveyed 40 students at her school and found that 0.55 of the students she surveyed said their favorite class is math. Ano

Leno4ka [110]

C.) 30 since they both have 5's just take them out then subtract 50 and 20 *but make sure u take out the decimal though* so after u subtract u will get 30 then line it up and put the decimal back then it will be .30

7 0

3 years ago

Find the product of all real values of r for which 1/2x=r-x/7

Dahasolnce [82]

Answer:

$r = \±\sqrt{14$

$Product = -14$

Step-by-step explanation:

Given

$\frac{1}{2x} = \frac{r - x}{7}$

Required

Find all product of real values that satisfy the equation

$\frac{1}{2x} = \frac{r - x}{7}$

Cross multiply:

$2x(r - x) = 7 * 1$

$2xr - 2x^2 = 7$

Subtract 7 from both sides

$2xr - 2x^2 -7= 7 -7$

$2xr - 2x^2 -7= 0$

Reorder

$- 2x^2+ 2xr -7= 0$

Multiply through by -1

$2x^2 - 2xr +7= 0$

The above represents a quadratic equation and as such could take either of the following conditions.

(1) No real roots:

This possibility does not apply in this case as such, would not be considered.

(2) One real root

This is true if

$b^2 - 4ac = 0$

For a quadratic equation

$ax^2 + bx + c = 0$

By comparison with $2x^2 - 2xr +7= 0$

$a = 2$

$b = -2r$

$c =7$

Substitute these values in $b^2 - 4ac = 0$

$(-2r)^2 - 4 * 2 * 7 = 0$

$4r^2 - 56 = 0$

Add 56 to both sides

$4r^2 - 56 + 56= 0 + 56$

$4r^2 = 56$

Divide through by 4

$r^2 = 14$

Take square roots

$\sqrt{r^2} = \±\sqrt{14$

$r = \±\sqrt{14$

Hence, the possible values of r are:

$\sqrt{14$ or $-\sqrt{14$

and the product is:

$Product = \sqrt{14} * -\sqrt{14}$

$Product = -14$

8 0

3 years ago