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4 years ago

I need help solving this:y+8x=4

Mathematics

2 answers:

slamgirl [31]4 years ago

6 0

Well there could be many possible outcomes for example it could be 2+8x0.25 while following pemdass

olga2289 [7]4 years ago

4 0

Y=0.5 because you need to divide 8 from 8x and 4. So the answer is y=0.5... I hope that helps.

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two sides of a triangle have the same length. the third side measures 6 m less than twice the common length. the perimeter of th

Y_Kistochka [10]

Let $x$ be the length of the two sides that are the same.

Then the third side would be $2x -3$ .

The perimeter of the triangle will come from adding all of the sides together and setting it equal to the value given, $13$ .

That is,

$x + x + (2x - 3) = 13$

$-- > 4x - 3 =13$

$-- > 4x = 16$

$-- > x = 4.$

As for the answer, the question was cut short, but with $x=4,$ ,

the length of each of the common sides is $4$ , making the third side $5$ , to get a total perimeter of $13$ .

<h3>What are two sides of a triangle?</h3>

The hypotenuse of a right-angled triangle is its longest side, the base is its lower side, and the perpendicular, which stands next to the right angle, is its standing line.

You may determine the sides of a right-angled triangle using a number of techniques, such as the Pythagoras theorem or the triangle's perimeter.

To learn more about sides of a triangle visit:

brainly.com/question/16986516

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5 0

1 year ago

A cubical water tank is 80 cm broad. find the volume of tank?

Tatiana [17]

Answer:

512000

Step-by-step explanation:

l=80cm

v=l^3

=80^3

=512000cm^3

7 0

3 years ago

1/6+1/12 Write the Awnser in lowest terms Show your work

Nezavi [6.7K]

Answer:

1/4

Step-by-step explanation:

1/6 + 1/12

Multiply the numerator and denominator of the first fraction by 2.

2/12 + 1/12

Add both fractions, because they have a common denominator.

3/12

The fraction can be further simplified.

1/4

6 0

3 years ago

Find the length of the third side to the nearest tenth 6 and 9

oee [108]

Hello, i do believe that you are asking me to do pythagorean theorem.

I'm not too sure if we are solving hypotenuse or a/b so i'll do both.

$\boxed{\underline{Hypotenuse...}}\\\\\\A^2+B^2=C^2\\6^2+9^2=C^2\;\\36+81=117$

$\sqrt{117}=10.816\\Round-\;10.8$

$\boxed{\underline{a/b...}}\\\\\\A^2=C^2-B^2\\A^2=9^2-6^2\\A^2=81-36\\A^2=45\\\sqrt{45}= 6.708\\Round-\;6.7$

Hope it helps!

6 0

3 years ago

FOR 20 POINTS!!!! Please help numbers 18, 19, and 20 i dont get them answers are good but it would be great if you explained the

cluponka [151]

Problem 18)

The distance from J to L is 30 units. We can count out the number of spaces or do subtraction to get 30-0 = 30. I subtracted the number line coordinate of J and L. The result is positive as distance is never negative.

Take 2/3 of this value to get (2/3)*30 = 20 which means that we start at J and add on 20 units to get 0+20 = 20

So the final answer is 20, which is where this point is located on the number line.
----------------------------------------------------------------
Problem 19)

The distance from A to B is 3 units because |-5-(-2)| = |-5+2| = |-3| = 3

Double this value to get 2*3 = 6

Now add 6 units to the coordinate of point A to get
-5+6 = 1

The location of this point is at 1 on the number line.
----------------------------------------------------------------
Problem 20)

From J to I, or vice versa, we travel 5 units.

Multiply this by 1.5 to get 1.5*5 = 7.5

So we subtract 7.5 units from 0 (the coordinate of point J) getting us 0-7.5 = -7.5

Final Answer: -7.5
Note: this is the midpoint of -10 and -5 on the number line

7 0

3 years ago