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3 years ago

Which is greater? 2.17 or 2.2

Mathematics

2 answers:

goldfiish [28.3K]3 years ago

8 0

Answer:

2.2

Step-by-step explanation:

zysi [14]3 years ago

8 0

Answer:

2.2 because the 2.2 can be 2.20

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Kiran scored 36 baskets in 1 week. She scored 1/2 of the baskets on the weekend. She scored 1/4 of them on Tuesday, she scored 1

notka56 [123]

Answer:

6 baskets did Kiran score on Thursday

Step-by-step explanation:

As per the statement:

Kiran scored 36 baskets in 1 week.

On weekend she scored = $\frac{1}{2} \cdot 36 = 18$ baskets.

She scored 1/4 of them on Tuesday

⇒On Tuesday she scored = $\frac{1}{4} \cdot 36 = 9$ baskets

She scored 1/12 of them on Wednesday

⇒On Wednesday she scored = $\frac{1}{12} \cdot 36 = 3$ baskets.

Then;

She scored = On Weekend + On Tuesday + On Wednesday = 18+9+3 = 30 baskets.

Rest on Thursday she scored = 36 - 30 = 6 baskets.

Therefore, 6 baskets did Kiran score on Thursday

8 0

3 years ago

Carla earns $13 an hour cleaning house. How much will she earn if she works from 8:00 to 2:00?

Andreyy89

8pm to 2am, or 8am to 2pm, either way, Carla would've worked for 6 hours.

6*$13=$78

-----------

Carla would earn $78 if she were to clean for 6 hours.

4 0

2 years ago

Read 2 more answers

Given that cot θ = 1/√5, what is the value of (sec²θ - cosec²θ)/(sec²θ + cosec²θ) ?

Bogdan [553]

Step-by-step explanation:

$\mathsf{Given :\;\dfrac{{sec}^2\theta - co{sec}^2\theta}{{sec}^2\theta + co{sec}^2\theta}}$

$\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{{sec}\theta = \dfrac{1}{cos\theta}}}}$

$\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{co{sec}\theta = \dfrac{1}{sin\theta}}}}$

$\mathsf{\implies \dfrac{\dfrac{1}{cos^2\theta} - \dfrac{1}{sin^2\theta}}{\dfrac{1}{cos^2\theta} + \dfrac{1}{sin^2\theta}}}$

$\mathsf{\implies \dfrac{\dfrac{sin^2\theta - cos^2\theta}{sin^2\theta.cos^2\theta}}{\dfrac{sin^2\theta + cos^2\theta}{sin^2\theta.cos^2\theta}}}$

$\mathsf{\implies \dfrac{sin^2\theta - cos^2\theta}{sin^2\theta + cos^2\theta}}$

Taking sin²θ common in both numerator & denominator, We get :

$\mathsf{\implies \dfrac{sin^2\theta\left(1 - \dfrac{cos^2\theta}{sin^2\theta}\right)}{sin^2\theta\left(1 + \dfrac{cos^2\theta}{sin^2\theta}\right)}}$

$\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{cot\theta = \dfrac{cos\theta}{sin\theta}}}}$

$\mathsf{\implies \dfrac{1 -cot^2\theta}{1 + cot^2\theta}}$

$\mathsf{Given :\;cot\theta = \dfrac{1}{\sqrt{5}}}$

$\mathsf{\implies \dfrac{1 - \left(\dfrac{1}{\sqrt{5}}\right)^2}{1 + \left(\dfrac{1}{\sqrt{5}}\right)^2}}$

$\mathsf{\implies \dfrac{1 - \dfrac{1}{5}}{1 + \dfrac{1}{5}}}$

$\mathsf{\implies \dfrac{\dfrac{5 - 1}{5}}{\dfrac{5 + 1}{5}}}$

$\mathsf{\implies \dfrac{5 - 1}{5 + 1}}$

$\mathsf{\implies \dfrac{4}{6}}$

$\mathsf{\implies \dfrac{2}{3}}$

Hence, option (a) 2/3 is your correct answer.

3 0

2 years ago

12. If 5t + 2 = 6, then t =

tankabanditka [31]

It would be t=0.8, mainly bc you subtract two from six , that reduces it to four
then you divide four by five and it should give you your answer
and to chack your work put .8 where t was and solve

6 0

3 years ago

Read 2 more answers

The following relations are written as equations. Which one is NOT a.

julia-pushkina [17]

Answer:

x = 4

Step-by-step explanation:

doesn't pass the vertical line test

8 0

3 years ago

Read 2 more answers