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elena-s [515]
3 years ago
15

4. Solve the shape equation puzzle: A+ A+ A+ B+ B=20 B+ A+ A=13

Mathematics
2 answers:
Katarina [22]3 years ago
8 0

Answer:

A = 6, B = 1.

Step-by-step explanation:

3A + 2B = 20

2A + B = 13          Multiply this by -2:

-4A - 2B = -26     Add this equation to the first equation:

-A = -6

A = 6.

and from the second equation:

2(6) + B = 13

B = 13 - 12 = 1.

Bingel [31]3 years ago
7 0

3A+2B=20

2A+B=13 ➡×(-2)➡-4A-2B=-26

3A+2B-4A-2B=20-26

-A=-6 ➡A=6

2(6)+B=13➡B=1

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Step-by-step explanation:

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4 0
3 years ago
The numbers 1, 2, 3, 4, 5, and 6 are placed in a line. How many even numbers can be made from these digits?
fiasKO [112]
<h3>Answer:    360</h3>

==========================================================

Explanation:

We have 3 even values (2,4, and 6) so this is the number of choices we have for the units digit. Recall that a number is even if the units digit is 0,2,4,6 or 8.

Once we have the units digit selected, we have 6-1 = 5 choices for the first slot, 6-2 = 4 choices for the second slot, and so on until we get down to 6-5 = 1 choice for the fifth slot

We could write it out like this

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GaryK [48]
Answer: cos(Θ) = (√15) / 4

Explanation:

The question states:

1) sin(Θ) = 1/4

2) 0 < Θ < π / 2

3) find cos(Θ)

This is how you solve it.

1) Use the fundamental identity (in this part I use α instead of Θ, just for facility of wirting the symbols, but they mean the same for the case).

(cos \alpha )^2 + (sin \alpha )^2 =1

2) From which you can find:

(cos \alpha )^2 = 1 - (sin \alpha )^2

3) Replace sin(α) with 1/4

=> (cos \alpha )^2 = 1 - (1/4)^2 = 1 - 1/16 = 15/16

=> cos \alpha =+/- \sqrt{15/16} = +/- (\sqrt{15} )/4

4) Given that the angle is in the first quadrant, you know that cosine is positive and the final answer is:

cos(Θ) = \sqrt{15} /4.

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6 0
3 years ago
Equivalent expression to 3y+4-6y-2
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