All categories

2 years ago

Which of the following represents 10 1/2 as a decimal?

Mathematics

2 answers:

denis23 [38]2 years ago

6 0

Answer:

Its 10.5

Step-by-step explanation:

The ten is a whole number and .5 is 5/10 or a half.

Have a great day.

Hatshy [7]2 years ago

3 0

Answer:

10.5

Step-by-step explanation:

10 1/2 = 10.5

You might be interested in

Which of the following sets would have a graph with an open circle on 2 and a ray pointing left on the number line?

MaRussiya [10]

Hi, the graph you describe represents all real numbers smaller than 2, without the two (that's why there's the open circle). Hence the correct answer is the third choice <span>{x | x ∈ R, x < 2}.

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
</span>

8 0

3 years ago

Need Help Please!!!!!!!!!!

gulaghasi [49]

You add each number by 6n - fourth choice. I am not sure if this is the right answer.

3 0

2 years ago

Read 2 more answers

For women at hartford college, times to run 400 meters are normally distributed with a mean of 84 seconds and a standard deviati

pashok25 [27]

z=(63-84)/3= -21/7= -3
P(x>63)=p(z > -3) = .9987 or 99.87%

4 0

3 years ago

In a shipment of 56 vials, only 13 do not have hairline cracks. If you randomly select 3 vials from the shipment, in how many wa

Elden [556K]

Answer: 27434

Step-by-step explanation:

Given : Total number of vials = 56

Number of vials that do not have hairline cracks = 13

Then, Number of vials that have hairline cracks =56-13=43

Since , order of selection is not mattering here , so we combinations to find the number of ways.

The number of combinations of m thing r things at a time is given by :-

$^nC_r=\dfrac{n!}{r!(n-r)!}$

Now, the number of ways to select at least one out of 3 vials have a hairline crack will be :-

$^{13}C_2\cdot ^{43}C_{1}+^{13}C_{1}\cdot ^{43}C_{2}+^{13}C_0\cdot ^{43}C_{3}\\\\=\dfrac{13!}{2!(13-2)!}\cdot\dfrac{43!}{1!(42)!}+\dfrac{13!}{1!(12)!}\cdot\dfrac{43!}{2!(41)!}+\dfrac{13!}{0!(13)!}\cdot\dfrac{43!}{3!(40)!}\\\\=\dfrac{13\times12\times11!}{2\times11!}\cdot (43)+(13)\cdot\dfrac{43\times42\times41!}{2\times41!}+(1)\dfrac{43\times42\times41\times40!}{6\times40!}\\\\=3354+11739+12341=27434$

Hence, the required number of ways =27434

5 0

2 years ago

The dimensions of prism B are 3 times the dimensions of prism A. The volume of prism A is 384cm cubed.

Anton [14]

The volume of prism B is 1,152

5 0

2 years ago