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antoniya [11.8K]

3 years ago

11

You have 15 coins in your pocket that are either quarters or dimes. They total $2.70. How many quarters do you have?

1 answer:

lana66690 [7]3 years ago

8 0

11 Quarters

25 50 75 1.00
1.25 1.50 1.75 2.00
2.25 2.50

2 Dimes
2.60 2.70

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A solid aluminum cube has sides each of length l . A second cube of the same material has sides four times the length of the fir

timofeeve [1]

The formula to find the volume of cube

cube = s^3

Therefore volume is equal to I^3

The second cube has 4x the First cube

4 × (I^3) = 4 ×I^3

Total volume of the second cube= 4I^3 cm3

Fact: the density(mass ÷ volume) of aluminium is 2.40g/cm3

Making mass the subject of the formula:

D = M ÷ V
(Times volume to remove deno minator)

Mass = Density × Volume

Mass = 2.40 × 4I ^3

Mass = 8.40I^3

By physics

weight= m × g

where
M = mass
g = acceleration due to gravity (= 9.8)

W = 8.40 I^3 × 9.8

Weight of aluminium = 82.32I^3

3 0

4 years ago

The largest set of x values satisfying

velikii [3]

Answer:

If $p\ge -\dfrac{1}{3},$ then $x>\dfrac{2}{3}+p$ and $mn=\dfrac{2}{3}+p=\left(\dfrac{2}{3}+p\right)\cdot 1,\ \ m+n=\dfrac{5}{3}+p$

Step-by-step explanation:

Solve two inequalities for x.

1. $2,018x-p$

Separate terms with x and without x into two sides:

$2,018x-2,020x$

Multiply by -1:

$2x>-2p\\ \\x>-p$

2. $7x+3p$

Separate terms with x and without x into two sides:

$7x-10x$

Multiply by -1:

$3x>2+3p\\ \\x>\dfrac{2}{3}+p$

Find the largest set of x values satisfying both inequalities:

$x>-p\\ \\x>\dfrac{2}{3}+p$

If

$-p>\dfrac{2}{3}+p\\ \\-2p>\dfrac{2}{3}\\ \\2p$

then $x>-p$ and $mn=-p=p\cdot (-1),\ m+n=p-1.$ In this case both m and n are negative.

If $p>-\dfrac{1}{3},$ then $x>\dfrac{2}{3}+p$ and $mn=\dfrac{2}{3}+p=\left(\dfrac{2}{3}+p\right)\cdot 1,\ \ m+n=\dfrac{5}{3}+p$

If $p=-\dfrac{1}{3},$ then $x>\dfrac{1}{3}$ and $mn=\dfrac{1}{3}=\dfrac{1}{3}\cdot 1,\ \ m+n=\dfrac{4}{3}$

7 0

3 years ago

Determine which rectangle was transformed to result in rectangle E

jenyasd209 [6]

Answer:

Rectangle C

Step-by-step explanation:

Rectangle C was transformed to Rectangle E.

To see how this occurs, let's follow point F (-2, 5) through the two transformations.

(a) Reflection across the x-axis

The x-coordinate does not change, but the y-coordinate changes sign.

Thus, F ⟶ F' (-2, -5).

(b) Translating up two units

The x-coordinate does not change, but the y-coordinate increases by 2..

Thus, F' ⟶ F" (-2, -3).

You can follow the same transformations for the other three corners of rectangle C.

Rectangle C ⟶ Rectangle E

3 0

3 years ago

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Blake made and 87 on the first semester of algebra 1 . What score can he make on the second semester if he wants his average to

Nadusha1986 [10]

Blake must score an average of at least a 93 on his second semester to be able to have an average of 90 for both semesters.

8 0

3 years ago

Evaluate the following expression for x = 2.<br> -36.8 + 9.2x

Gala2k [10]

Answer: -18.4

Step-by-step explanation:

-36.8 + 9.2x, when x = 2

Replace x with 2

-36.8 + 9.2(2)

= -36.8 + 18.4

= -18.4

I hope this helps.

6 0

3 years ago

Read 2 more answers