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vovangra [49]
4 years ago
14

During a 12-hour period, the temperature in a city dropped from a high of 66°F to a low of −29°F. What was the range of the temp

eratures during this period?
Mathematics
1 answer:
LenaWriter [7]4 years ago
7 0

Answer:

95

Step-by-step explanation:

66-66=0

0-29=-29

66+29=95

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Fill in the blanks to complete the steps for finding the equation of a parallel line.
gtnhenbr [62]

Answer:

1.point-slope

2.slope

Step-by-step explanation:

4 0
3 years ago
In the diagram, △ABC∼△DEF. The area of △ABC is 180 square centimeters. Find the area of △DEF.
Alexeev081 [22]

Answer:

20

Step-by-step explanation:

The first step is to find out the similarity reason of the sides of the triangle, so we just divide the big side by the small side (12/4=3).

Now, for the similarity reason of the areas, we just square that number (3^2=9).

Then we just divide the area of the big triangle by 9, which is 180/9= 20.

4 0
3 years ago
Read 2 more answers
Henry has just moved to England and is trying to continue his lawn care business. He needs to buy gas for his lawnmower. He has
Harrizon [31]
I have no idea but i know that its 11 qUARTS ALL TOGETHer
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3 years ago
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Suppose x=c1e−t+c2e3tx=c1e−t+c2e3t. Verify that x=c1e−t+c2e3tx=c1e−t+c2e3t is a solution to x′′−2x′−3x=0x′′−2x′−3x=0 by substitu
Harrizon [31]

The correct question is:

Suppose x = c1e^(-t) + c2e^(3t) a solution to x''- 2x - 3x = 0 by substituting it into the differential equation. (Enter the terms in the order given. Enter c1 as c1 and c2 as c2.)

Answer:

x = c1e^(-t) + c2e^(3t)

is a solution to the differential equation

x''- 2x' - 3x = 0

Step-by-step explanation:

We need to verify that

x = c1e^(-t) + c2e^(3t)

is a solution to the differential equation

x''- 2x' - 3x = 0

We differentiate

x = c1e^(-t) + c2e^(3t)

twice in succession, and substitute the values of x, x', and x'' into the differential equation

x''- 2x' - 3x = 0

and see if it is satisfied.

Let us do that.

x = c1e^(-t) + c2e^(3t)

x' = -c1e^(-t) + 3c2e^(3t)

x'' = c1e^(-t) + 9c2e^(3t)

Now,

x''- 2x' - 3x = [c1e^(-t) + 9c2e^(3t)] - 2[-c1e^(-t) + 3c2e^(3t)] - 3[c1e^(-t) + c2e^(3t)]

= (1 + 2 - 3)c1e^(-t) + (9 - 6 - 3)c2e^(3t)

= 0

Therefore, the differential equation is satisfied, and hence, x is a solution.

4 0
3 years ago
Let ​ f(x)=x+2f(x)=x+2 ​ and ​ g(x)=2^X+1 ​
Lemur [1.5K]
For this case, what you must do is to graph both functions in the same coordinate plane and verify where they are cut.
 The points where they are cut will be solutions for f (x) = g (x).
 This particular function is cut into two points:
 (0, 2)
 (1, 3)
 Therefore, the solution for f (x) = g (x) is
 x = 0
 x = 1
 answer
<span> the solutions to the equation are 
</span> x = 0
 x = 1

8 0
4 years ago
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