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navik [9.2K]
3 years ago
6

URGENT WILL MARK BRAINLIEST

Mathematics
1 answer:
ira [324]3 years ago
3 0

Answer:

1. Equation: P=90N+2,100

2. Total pay if Henry sells 27 copies: 4,530\$

Step-by-step explanation:

1. The equation of the line in Slope-Intercept form is:

y=mx+b

Where "m" is the slope and "b" is the y-intercept.

According to the information given in the exercise, his base salary is $2,100. So you can identify that:

b=2,100

Since he makes an additional of $90 for every copy of he sells, you can identify that:

m=90

Therefore, the equation that represents this situation is:

P=90N+2,100

2. If he sells 27 copies, then:

N=27

Substituting this value into the equation, you get that his total pay would be:

P=90(27)+2,100\\\\P=4,530

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The answer is 4 1/8 or 33/8 as a improper fraction.
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I run a book club with n people, not including myself. Every day, for 365 days, I invite three members in the club to review a b
Bezzdna [24]
<h3>Answer:   15</h3>

========================================================

Explanation:

The order doesn't matter. A group like {A,B,C} is the same as {B,A,C}.

All that matters is the overall group rather than the positioning of the members.

We'll use the nCr combination formula since order doesn't matter.

The value of n is unknown, but we know that r = 3 members are to be selected.

Let's pick a value for n at random. Let's say n = 10.

Plug n = 10 and r = 3 into the nCr formula below.

n C r = \frac{n!}{r!(n-r)!}\\\\10 C 3 = \frac{10!}{3!*(10-3)!}\\\\10 C 3 = \frac{10!}{3!*7!}\\\\10 C 3 = \frac{10*9*8*7!}{3!*7!}\\\\ 10 C 3 = \frac{10*9*8}{3!}\\\\ 10 C 3 = \frac{10*9*8}{3*2*1}\\\\ 10 C 3 = \frac{720}{6}\\\\ 10 C 3 = 120\\\\

Unfortunately we don't reach 365 or larger.

Let's try n = 11

n C r = \frac{n!}{r!(n-r)!}\\\\11 C 3 = \frac{11!}{3!*(11-3)!}\\\\11 C 3 = \frac{11!}{3!*8!}\\\\11 C 3 = \frac{11*10*9*8!}{3!*8!}\\\\ 11 C 3 = \frac{11*10*9}{3!}\\\\ 11 C 3 = \frac{11*10*9}{3*2*1}\\\\ 11 C 3 = \frac{990}{6}\\\\ 11 C 3 = 165\\\\

We're still under our target. The good news is that the nCr value is increasing.

So the idea is to do trial and error with various values of n. Keep incrementing n until nCr = nC3 is equal to 365 or larger.

Here's a table of values where r = 3 the entire time

\begin{array}{|c|c|} \cline{1-2}\text{n} & \text{nCr}\\\cline{1-2}10 & 120\\\cline{1-2}11 & 165\\\cline{1-2}12 & 220\\\cline{1-2}13 & 286\\\cline{1-2}14 & 364\\\cline{1-2}15 & 455\\\cline{1-2}\end{array}

The nCr values are also found in Pascal's Triangle. Each of those values are the fourth entry of each row.

When n = 14, we have nCr = 364 which is very close. We're one short unfortunately.

So we have to go for <u>n = 15</u> instead. This makes the nCr value well over 365 of course, but it guarantees that you'll have plenty of trios to choose from such that no group of three is repeated. Unfortunately some trios will be left out.

7 0
2 years ago
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Now we will find the speed of the car at another point B(1, 60).

If the speed of car is same as the point B as of point A, point B will lie on the graph.

Speed of the car at B(1, 60) = \frac{\text{Distance traveled}}{\text{Time}}

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8 0
3 years ago
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In the question, we are asked to find the equation of the line in point-slope form, that passes through the point (-3, 6) and has a slope m = -1/2.

We know that the equation of a line that has a slope m, and passes through the point (x₁, y₁) is given by the point-slope form of a line, which can be shown as:

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Taking (x₁, y₁) as (-3, 6) and m = -1/2, in the point-slope form, we get the equation of the line as;

y - 6 = (-1/2)(x - (-3)).

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or, x + 2y = 9.

Thus, the equation of the line in point-slope form is <u>y - 6 = (-1/2)(x - (-3))</u> which can be simplified as <u>x + 2y = 9</u>.

Learn more about the point-slope form at

brainly.com/question/11624671

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4 0
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