All categories

2 years ago

Find the mean, median, and mode 15,3,11,15,1,14,7,2,1,1,2

Mathematics

2 answers:

Aloiza [94]2 years ago

5 0

Mean= 6.5
Median= 3
Mode= 1

I swrear on my life this is right please rate brainiest answer thx

FinnZ [79.3K]2 years ago

4 0

Count:11

Sum:72

Mean:6.54

Median:3

Mode:1
Hope I helped ;)

You might be interested in

Is a tray with a circumference of 32 inches is big enough to

yKpoI14uk [10]

Answer:

Yes

Step-by-step explanation:

Circumference formula is C=2 pi r, if you divide the pizza by 2 to get the radius,5, then input it into the formula to get 31.41592654, and since this number is smaller than 32 it will fit. If 10 is the radius it will not fit.

7 0

2 years ago

F(x) = 2(x+3)2 -7 a= h= k=

vlabodo [156]

Answer:

Step-by-step explanation:

In vertex form, the equation is

y = a(x-h)^2 + k

So just read off the values!

6 0

2 years ago

Determine formula of the nth term 2, 6, 12 20 30,42

nalin [4]

Check the forward differences of the sequence.

If $\{a_n\} = \{2,6,12,20,30,42,\ldots\}$ , then let $\{b_n\}$ be the sequence of first-order differences of $\{a_n\}$ . That is, for n ≥ 1,

$b_n = a_{n+1} - a_n$

so that $\{b_n\} = \{4, 6, 8, 10, 12, \ldots\}$ .

Let $\{c_n\}$ be the sequence of differences of $\{b_n\}$ ,

$c_n = b_{n+1} - b_n$

and we see that this is a constant sequence, $\{c_n\} = \{2, 2, 2, 2, \ldots\}$ . In other words, $\{b_n\}$ is an arithmetic sequence with common difference between terms of 2. That is,

$2 = b_{n+1} - b_n \implies b_{n+1} = b_n + 2$

and we can solve for $b_n$ in terms of $b_1=4$ :

$b_{n+1} = b_n + 2$

$b_{n+1} = (b_{n-1}+2) + 2 = b_{n-1} + 2\times2$

$b_{n+1} = (b_{n-2}+2) + 2\times2 = b_{n-2} + 3\times2$

and so on down to

$b_{n+1} = b_1 + 2n \implies b_{n+1} = 2n + 4 \implies b_n = 2(n-1)+4 = 2(n + 1)$

We solve for $a_n$ in the same way.

$2(n+1) = a_{n+1} - a_n \implies a_{n+1} = a_n + 2(n + 1)$

Then

$a_{n+1} = (a_{n-1} + 2n) + 2(n+1) \\ ~~~~~~~= a_{n-1} + 2 ((n+1) + n)$

$a_{n+1} = (a_{n-2} + 2(n-1)) + 2((n+1)+n) \\ ~~~~~~~ = a_{n-2} + 2 ((n+1) + n + (n-1))$

$a_{n+1} = (a_{n-3} + 2(n-2)) + 2((n+1)+n+(n-1)) \\ ~~~~~~~= a_{n-3} + 2 ((n+1) + n + (n-1) + (n-2))$

and so on down to

$a_{n+1} = a_1 + 2 \displaystyle \sum_{k=2}^{n+1} k = 2 + 2 \times \frac{n(n+3)}2$

$\implies a_{n+1} = n^2 + 3n + 2 \implies \boxed{a_n = n^2 + n}$

6 0

2 years ago

Jenny drives from Paris to Rochefort, a distance of 483 km. her average speed on the journey is 84 km/h, she leaves at 9:50. Wha

Mrrafil [7]

The correct answer is 3: 35

Explanation:

To calculate at what time Jenny will arrive in Rochefort, the first step is to calculate the approximate time of the trip. Now, to calculate this consider the time of a movement (t) equals to the distance (d) divided by the speed (s), the process is shown below:

t = 483 km / 84 km/h

t = 5.75 hours

In this number 5 refers to the hours and 0.75 represents 45 minutes considering 0.75 x 60 minutes in one hour = 45 minutes. Therefore, the total time from Paris to Rochefort is 5 hours and 45 minutes. Now, to calculate the time of arrival add this result to the time of departure.

Add the hours: 5 hours + 9 hours: 14 hours

Add the minutes: 50 minutes + 45 minutes =95 minutes

95 minutes are equivalent to 1 hour (60) minutes and 35 minutes

Calculate the total

Hours: 14 hours + 1 hour = 15 hours or 3 in the 12 hour system (15 hours - 12 hours = 3 p.m.)

Minutes: 35 minutes

4 0

3 years ago

One month, ruby worked 8 hours more than isaac, and svetlana worked 4 times as many hours as ruby. together they worked 136 hour

Travka [436]

Let Issac work for x hours, and Ruby works 8 hours more than of Issac, so Ruby work for $(x+8)$ hours.

And Svetlana worked four times of Ruby, therefore Svetlana worked for

$4(x+8) hours$

And total hours they worked together is 136. That is

$x+x+8 + 4(x+8) = 136
\\
x+x+8 +4x+32=136
\\
6x+40 =136
\\
6x=96
\\
x =16 hours$

So Issac worked for 16 hours, Ruby worked for 24 hours and Svetlana worked for 24 times 4 equals 96 hours .

6 0

3 years ago