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Makovka662 [10]
3 years ago
8

A veterinarian does research on the causes of enteroliths, stones that develop in the colon of horses. She suspects that feeding

alfalfa might be a cause. To investigate that suspicion, she selects five horses that are known to have enteroliths and compares the number of flakes of alfalfa they have eaten over a month with the number of flakes eaten by five horses free of enteroliths. She calculates a two‑sample confidence interval for the difference in means and finds that it includes zero. Therefore, she can conclude that: all horses get exactly the same amount of alfalfa each month whether or not they have enteroliths. on average, horses with and without enteroliths are fed the same amount of alfalfa per month. all horses get exactly the same amount of alfalfa each day whether or not they have enteroliths. the 10 horses in the sample were fed exactly the same amounts of alfalfa.
Mathematics
1 answer:
dsp733 years ago
7 0

Answer:

On average, horses with and without enteroliths are fed the same amount of alfalfa per month

Step-by-step explanation:

Hello!

The veterinarian wants to research if eating alfalfa causes horses to have enteroliths.

The study variables are:

X₁: number of alfalfa flakes eaten over a month by a horse with enteroliths.

X₂: number of alfalfa flakes eaten over a month by a horse free of enteroliths.

She calculated a CI interval, with level 1 - α and the interval contained the cero.

With a significance level α, the hypotheses are:

H₀: μ₁ - μ₂ = 0

H₁: μ₁ - μ₂ ≠ 0

To decide whether you should reject or not the null hypothesis using a Confidence Interval is the following:

If the CI contains the number stated in the null hypothesis, the decision is to not reject the null hypothesis.

If the CI doesn't contain the number stated in the null hypothesis, then the decision is to reject the null hypothesis.

Since the interval contains the cero, if 1 - α and α are complementary, the decision is to reject the null hypothesis.

This means that at a level of significance of α, you can conclude that there is no difference between the population means of the numbers of alfalfa flakes eaten by horses with or without enteroliths.

I hope it helps!

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ivanzaharov [21]

The weather that is most likely to occur where Richard is is rain shower.

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Weather is the state of the atmosphere of a particular place over a short period of time. There is low atmospheric pressure, so it is likely that it would rain. This is because when the  atmospheric pressure is low, it is likely that it would rain.

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3 years ago
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Solve the inequality for u<br>-5u+27 [less than or equal to] 2​
baherus [9]

Answer:

5≤u

Step-by-step explanation:

Put the words and numbers into an equation:

-5u+27≤2

Put all like terms on one side:

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Simplify:

25≤5u

Solve:

5≤u

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3 years ago
Solve the given system of equations <br> 2x+8y=5<br> 24x-4y=-15
oee [108]

The value of x and y is y= 3/4 and x= -1/2

<h3>What is equation?</h3>

An equation is a mathematical expression that contains an equals symbol. Equations often contain algebra.

Given equations:

2x+8y=5........(1)

24x-4y=-15...........(2)

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24x + 96y = 60.....(3)

From (2) and (3), we get

-4y-96y= -15-60

-100 y= -75

y= -75/-100

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and 2x+8y=5

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2 years ago
If jana drives 6 hours at a speed of 60 miles/hour and 9 hours at a speed of 62 miles/hour, what is her average speed in miles/h
sergejj [24]

Answer:

c) (61.20)

Step-by-step explanation:

6*60=360

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360+558=918

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3 0
4 years ago
The accompanying data represent the miles per gallon of a random sample of cars with a three-cylinder, 1.0 liter
astraxan [27]

Answer:

A) Z = -0.24

We can interpret this as the z-score corresponding to the individual who obtained 38. 1 miles per gallon is -0.24.

B) Q1 = 36.8 and Q3 = 41

C)IQR = 4.2

This means that the distance between the first and third quartile is 4.2

D) LF = 30.5 and UF = 47.3

the only outlier is 48.9 which is more than UF

Step-by-step explanation:

We are given the data representing the miles per gallon of a random sample of cars with a three-cylinder as;

32.7, 35.7, 38.0, 38.7, 40.1, 42.3, 34.3, 36.2, 38.1, 39.0, 40.6, 42.9, 34.5, 37.4, 38.3, 39.4, 41.4, 43.4, 35.3, 37.6, 38.5, 39.7, 41.7, 48.9

Sum of data is;

ΣX = 32.7 + 35.7 + 38.0 + 38.7 + 40.1 + 42.3 + 34.3 + 36.2 + 38.1 + 39.0 + 40.6 + 42.9 + 34.5 + 37.4 + 38.3 + 39.4 + 41.4 + 43.4 + 35.3 + 37.6 + 38.5 + 39.7 + 41.7 + 48.9 = 934.7

Formula for mean is;

μ = ΣX/n

μ = 934.7/24

μ = 38.95

Formula for sample standard deviation of is;

s = √[(1/(n - 1))Σ(X - μ)²]

From online calculator, we have a value of;

s = 3.505

A) Formula for z-score is;

Z = (x - μ)/s

We are given x = 38.1

Thus;

Z = (38.1 - 38.95)/3.505

Z = -0.24

We can interpret this as the z-score corresponding to the individual who obtained 38. 1 miles per gallon is -0.24.

B) Arranging the set of given values in ascending order, we have;

32.7, 34.3, 34.5, 35.3, 35.7, 36.2, 37.4, 37.6, 38.0, 38.1, 38.3, 38.5, 38.7, 39.0, 39.4, 39.7, 40.1, 40.6, 41.4, 41.7, 42.3, 42.9, 43.4, 48.9

Number of data; n = 24

First quartile is;

Q1 = ((n + 1)/4)th = ((24 + 1)/4)th = 25/4 = 6.25th term

Thus, we will find the average of the 6th and 7th term;

Q1 = (36.2 + 37.4)/2

Q1 = 36.8

Similarly;

Q3 = ¾(n + 1)th = ¾(24 + 1)

Q3 = ¾ × 25 = 18.75th term

Thus, we will find the average of the 18th and 19th term.

Q3 = (40.6 + 41.4)/2

Q3 = 41

C) Formula for inter quartile range is;

IQR = Q3 - Q1

IQR = 41 - 36.8

IQR = 4.2

This means that the distance between the first and third quartile is 4.2

D) Formula for lower fence is;

LF = Q1 - (1.5 × IQR)

LF = 36.8 - (1.5 × 4.2)

LF = 30.5

Formula for upper fence is;

UF = Q3 + (1.5 × IQR)

UF = 41 + (1.5 × 4.2)

UF = 47.3

Now, an outlier will be any values in the given set less than LF or more than UF.

From the given set, the only outlier is 48.9 which is more than UF

4 0
3 years ago
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