For this case we can make the following rule of three:
23000 -------> 100%
x --------------> 180%
Clearing the value of x we have:
x = (180/100) * (23000)
x = 41400
Answer:
you would expect about:
a) 41,400 responses
0.0006 would be your answer based on the order you put them in.
Answer:
For tingle #1
We can find angle C using the triangle sum theorem: the three interior angles of any triangle add up to 180 degrees. Since we know the measures of angles A and B, we can find C.



We cannot find any of the sides. Since there is noting to show us size, there is simply just not enough information; we need at least one side to use the rule of sines and find the other ones. Also, since there is nothing showing us size, each side can have more than one value.
For triangle #2
In this one, we can find everything and there is one one value for each.
- We can find side c
Since we have a right triangle, we can find side c using the Pythagorean theorem






- We can find angle C using the cosine trig identity




- Now we can find angle A using the triangle sum theorem



For triangle #3
Again, we can find everything and there is one one value for each.
- We can find angle A using the triangle sum theorem



- We can find side a using the tangent trig identity




- Now we can find side b using the Pythagorean theorem




3 x - 7 = 5 x + 13
3 x - 5x = 13 + 7
-2x = 20
x = 20 / -2
x = - 10
Answer:
<h2><em>
38°, 66° and 76°</em></h2>
Step-by-step explanation:
A triangle consists of 3 angles and sides. The sum of the angles in a triangle is 180°. Let the angle be <A, <B and <C.
<A + <B + <C = 180° ...... 1
If the measure of one angle is twice the measure of a second angle then
<A = 2<B ...... 2
Also if the third angle measures 3 times the second angle decreased by 48, this is expressed as <C = 3<B-48............ 3
Substituting equations 2 and 3 into 1 will give;
(2<B) + <B + (3<B-48) = 180°
6<B- 48 = 180°
add 48 to both sides
6<B-48+48 = 180+48
6<B = 228
<B = 228/6
<B =38°
To get the other angles of the triangle;
Since <A = 2<B from equation 2;
<A = 2(38)
<A = 76°
Also <C = 3<B-48 from equation 3;
<C = 3(38)-48
<C = 114-48
<C = 66°
<em>Hence the measures of the angles of the triangle are 38°, 66° and 76°</em>