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ra1l [238]
2 years ago
15

In triangle ABC, the right angle is at vertex C, a = 714 cm and the measure of angle A is 78° . To the nearest cm, what is the l

ength of side c?
Mathematics
1 answer:
Contact [7]2 years ago
3 0

Answer:

c = 730 cm

Step-by-step explanation:

To solve this question we just need to use the law of sines:

The ratio between a side in the triangle and its opposite angle is always the same.

So we have that:

a / sin(A) = c / sin(C)

714 / sin(78) = c / sin(90)

sin(78) is equal 0.9781 and sin(90) is equal 1, so we have:

714 / 0.9781 = c / 1

c = 714 / 0.9781 = 730\ cm

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C

Step-by-step explanation:

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What is the answer to this please someone explain ​
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Answer:

D

Step-by-step explanation:

Divide the composite shape into 2 rectangles.

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Then, we plug in the values.

1st Rectangle

7 * (14 + 10)

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2nd Rectangle

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5 0
2 years ago
I'm having trouble graphing this problem: y=3/5x
Nady [450]

Answer:

(the slope is 3/5)

Hope this helps :)

6 0
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Solve the inequality.<br><br> 2(4 + 2x) ≥ 5x + 5?<br><br> x ≤ ?
NikAS [45]
2(4+2x)≥5x+5
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5 0
3 years ago
Read 2 more answers
Suppose that 40 percent of the drivers stopped at State Police checkpoints in Storrs on Spring Weekend show evidence of driving
lesantik [10]

Answer:

a) 0.778

b) 0.9222

c) 0.6826

d) 0.3174

e) 2 drivers

Step-by-step explanation:

Given:

Sample size, n = 5

P = 40% = 0.4

a) Probability that none of the drivers shows evidence of intoxication.

P(x=0) = ^nC_x P^x (1-P)^n^-^x

P(x=0) = ^5C_0  (0.4)^0 (1-0.4)^5^-^0

P(x=0) = ^5C_0 (0.4)^0 (0.60)^5

P(x=0) = 0.778

b) Probability that at least one of the drivers shows evidence of intoxication would be:

P(X ≥ 1) = 1 - P(X < 1)

= 1 - P(X = 0)

= 1 - ^5C_0 (0.4)^0 * (0.6)^5

= 1 - 0.0778

= 0.9222

c) The probability that at most two of the drivers show evidence of intoxication.

P(x≤2) = P(X = 0) + P(X = 1) + P(X = 2)

^5C_0  (0.4)^0  (0.6)^5 + ^5C_1  (0.4)^1  (0.6)^4 + ^5C_2  (0.4)^2  (0.6)^3

= 0.6826

d) Probability that more than two of the drivers show evidence of intoxication.

P(x>2) = 1 - P(X ≤ 2)

= 1 - [^5C_0  (0.4)^0  (0.6)^5 + ^5C_1  (0.4)^1  (0.6)^4 + ^5C_2 * (0.4)^2  (0.6)^3]

= 1 - 0.6826

= 0.3174

e) Expected number of intoxicated drivers.

To find this, use:

Sample size multiplied by sample proportion

n * p

= 5 * 0.40

= 2

Expected number of intoxicated drivers would be 2

7 0
2 years ago
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