The sum of the two <em>rational</em> equations is equal to (3 · n² + 5 · n - 10) / (3 · n³ - 6 · n²).
<h3>How to simplify the addition between two rational equations</h3>
In this question we must use <em>algebra</em> definitions and theorems to simplify the addition of two <em>rational</em> equations into a <em>single rational</em> equation. Now we proceed to show the procedure of solution in detail:
- (n + 5) / (n² + 3 · n - 10) + 5 / (3 · n²) Given
- (n + 5) / [(n + 5) · (n - 2)] + 5 / (3 · n²) x² - (r₁ + r₂) · x + r₁ · r₂ = (x - r₁) · (x - r₂)
- 1 / (n - 2) + 5 / (3 · n²) Associative and modulative property / Existence of the multiplicative inverse
- [3 · n² + 5 · (n - 2)] / [3 · n² · (n - 2)] Addition of fractions with different denominator
- (3 · n² + 5 · n - 10) / (3 · n³ - 6 · n²) Distributive property / Power properties / Result
To learn more on rational equations: brainly.com/question/20850120
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Partial Answer:
For #10 the solutions are 2 and 5
Step-by-step explanation:
Solutions for an equation can be x-intercepts, or where it touches the x or horizontal line. The equation in #10 touches the x line at 2 and 5.
(g*f)(0)= (x^3)*(2x+6)
(g*f)(0)= (0^3)*(2(0)+6)
(g*f)(0)= (0)*(0+6)
(g*f)(0)= (0)*(6)
(g*f)(0)= 0
Answer:
x = -1
Step by step explanation:
Distribute 6
6x-12= -18
Add 12 to both sides
6x= -6
Divide both sides by 6
x= -1
Hope this helps
Answer:
No
Step-by-step explanation:
x y
y = - 3(-2) + 1 = 7 -2 7
y = -3(0) +1 = 1 0 1
y = -3(1) + 1 = -2 1 -2
y = -3(3) + 1 = -8 3 -8
