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mojhsa [17]
4 years ago
8

!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
Thepotemich [5.8K]4 years ago
4 0
?????????????????????
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Find all the polynomials f (t ) of degree ≤ 2 [of the form f (t) = a + bt + ct2] whose graphs run through the points (1, 3) and
Ugo [173]

Answer:

f(t) = 4 - 3t + 2t^2

Step-by-step explanation:

Given:

f(t) = a + bt + ct^2

Differentiate w.r.t. "t"

f'(t) = b + 2ct

1) f(1) = 3

a + b +c = 3...........1)

2) f(2) = 6

a + 2b + 4c = 6.........2)

3) f'(1) = 1

b + 2c = 1 ...............3)

Solving above three simultaneous equations:

a = 4

b = -3

c = 2

Therefore equation becomes:

f(t) = 4 + (-3)t + (2)t^2

3 0
3 years ago
Help! And plz do explain...
Nat2105 [25]
1 mile is 5280 feet, therefore, we have 60 miles, and each mile is 5280 feet, so we multiply 5280 and 60, you get the answer of 316,800 feet.
6 0
3 years ago
Does anyone minding helping me with exterior angles ? due in 2 days
Goryan [66]

Answer:

x=25

Step-by-step explanation:

(x+40)+(3x+10)=6x

4x+50=6x

50=2x

25=x

5 0
3 years ago
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Fractions that have the same denominators are said to have <br> denominators.
zepelin [54]

Answer: Like fractions

7 0
3 years ago
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Please help I'm struggling so bad right now
Over [174]

Answer:

y = m x + b     is the standard form of a straight line

m = (y2 - y1) / (x2 - x1) = (10 - (-8)) / (-3 - 0) = 18 / -3 = -6

When x = 0 y = b from the equation for a line

y = - 8

So our equation is  

y = -6 x - 8

As a check let x = -2 then

y = (-6 * -2) - 8 = 12 - 8 = 4

Check on the graph to verify that this equation holds

8 0
3 years ago
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